What is the sum of the digits in the number one million( ).A. oneB. one hundred
CObserve that 2019_(10)=5613_7.To maximize the sum of the digits, we want as many 65 as possible (since 6 is the highest value in base ), and this will occur with either of the numbers 4666_i or 5566_i.Thus, the answer is 4+6+6+6=(122..∼IronicNinja, edited by some peo...
Statement-1: the sum of the diigits in the ten's place of all numbers formed with the help of 3,4,5,6 taken all at a time is 108. Statement-2: The sum of the digits in the ten's place= The sum of the digits is the units's place. ...
Find the sum of the digits in the number n! Input one line: n (1<n<=10000) Output the sum of the digits in the number n! Sample Input 10 Sample Output 27 Hint 10! = 3628800 3+6+2+8+8+0+0 = 27 【分析】 这道题如果用第一种方法,会超时 那还是用“万进制”吧! 如果哪位读者...
The sum of the digits in the unit place of all the numbers formed with the help of 3,4,5,6 taken all at a time is
Thus, the answer is 4+6+6+6=(C)22.. ∼IronicNinja, edited by some people, Note: the number can also be 55667, which will also give the answer of 22. Note that all base 7 numbers with 5 or more digits are in fact greater than 2019. Since the first answer that is possible us...
C. one thousandD. one million相关知识点: 试题来源: 解析 A One million 1000000, Adding, 1+9+0+0+0+0+0=1. 一百万的数字之和是( ). A.1 B.100 C.1000 D.1000000 一百万就等于1000000,所以1+0+0+0+0+0+0=1. 故选A.反馈 收藏 ...
http://codeforces.com/contest/489/problem/C 大数就是从最高位,能大就大;小数就是从最低位,能小就小,再处理下最高位为0的情况。 无结果无非一个sum太小,min全为0,一个sum太大,全为9还有剩 1publicclassMain {2publicstaticvoidmain(String[] args) {3Scanner io =newScanner(System.in);4intlen ...
If 1050 – 74 is written as an integer in base 10 notation,what is the sum of the digits in that integer?A.424B.433C.440D.449E.467是10^50 扫码下载作业帮搜索答疑一搜即得 答案解析 查看更多优质解析 解答一 举报 10^50 51位-74 50位后两位是26,前面48位是99*48+2+6=440C 解析看不懂...
A find the decimal expamsion for 1/43B show that 9 is a factor of the sum of the digits in the repetend of 1/7.1/39,1/43C suppose none of 2,3,5 is a factor of n.Explain why 9 is a factor of the sum ofthe digits in the repetend in the repetend of 1/nD Find the ...