n = x[(x % 3 == 0) | (x % 5 == 0)]: This line creates a boolean mask for elements in ‘x’ that are divisible by 3 or 5. The % operator computes the remainder of the division, and == 0 checks if the remainder is 0. The | operator is a boolean OR, which combines th...
975. Consider the properties of sums. The sum of two consecutive numbers must be odd. The sums of three consecutive numbers and of five consecutive numbers must be multiples of 3 and of 5 respectively. (Consider the 3 consecutive numbers n, n+1, and n+2. Their sum is 3n+3, which ...
975. Consider the properties of sums. The sum of two consecutive numbers must be odd. The sums of three consecutive numbers and of five consecutive numbers must be multiples of 3 and of 5 respectively. (Consider the 3 consecutive numbers n, n+1, and n+2. Their sum is 3n+3, which ...
"Sum the multiples of all of {:?} which are less than {}", factors, limit ) }3. 测试代码查看#[test] fn multiples_one() { assert_eq!(0, sum_of_multiples(1, &[3, 5])) } #[test] //#[ignore] fn multiples_two() { assert_eq!(3, sum_of_multiples(4, &[3, 5])) } ...
Find the sum of all the multiples of 3 or 5 below 1000. A: #! /usr/bin/env python #method 1 find = reduce(lambda x,y:x+y,[x for x in xrange(3,1000) if not x%3 or not x%5]) print find #method 2 result = 0
deftest_sum_to_1000(self):self.assertEqual(233168,sum_of_multiples(1000, [3,5])) 开发者ID:a62mds,项目名称:exercism,代码行数:2,代码来源:sum_of_multiples_test.py 示例6: test_multiples_of_zero_will_be_none ▲点赞 1▼ deftest_multiples_of_zero_will_be_none(self):self.assertEqual(sum...
百度试题 结果1 题目Find the sum of the first 3 multiples ofA. 7 B. 28 C. 56 D. 84 E. 140 相关知识点: 试题来源: 解析 C 14+28+42=84.反馈 收藏
Mathematics - Number Theory11A63We obtain a simple relations for the Newman sum over multiples of a prime with a primitive or semiprimitive root 2. We consider the case of p=17 as well.doi:10.48550/arXiv.0710.1354Shevelev, VladimirEprint Arxiv...
Find the sum of the lst ,4th and 7th multiples of 13选择语言:从 到 翻译结果1翻译结果2 翻译结果3翻译结果4翻译结果5 翻译结果1复制译文编辑译文朗读译文返回顶部 找到13的lst,第4次和第7的倍数的总和 翻译结果2复制译文编辑译文朗读译文返回顶部 发现lst 的总和, 13 的第 4 个和第 7 个倍数 翻译...
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