给定一个二叉树,它的每个结点都存放一个0-9的数字,每条从根到叶子节点的路径都代表一个数字。 例如,从根到叶子节点路径1->2->3代表数字123。 计算从根到叶子节点生成的所有数字之和。 说明:叶子节点是指没有子节点的节点。 示例1: 输入: [1,2,3]1 / \ 2 3输出: 25解释:从根到叶子节点路径 1->2...
404. Sum of Left LeavesEasy Topics Companies Given the root of a binary tree, return the sum of all left leaves. A leaf is a node with no children. A left leaf is a leaf that is the left child of another node. Example 1: Input: root = [3,9,20,null,null,15,7] Output: 24 ...
2、分析 这道题和124题有点像,只不过124更难一点,这道题只需要将所有到叶子节点的值计算出来再计算和。需要注意的是,必须是叶子节点,也就是说递归结束的条件是当前节点的左子树右子树都为空时才结束。之后递归分别计算左子树和右子树即可。 3、代码 /** * Definition for a binary tree node. * struct Tre...
Right != nil { result += dfs(root.Right, pathSum + root.Right.Val) } return result } 题目链接: Sum Root to Leaf Numbers : leetcode.com/problems/s 求根节点到叶节点数字之和: leetcode.cn/problems/su LeetCode 日更第 365 天,感谢阅读至此的你 欢迎点赞、收藏、在看鼓励支持小满...
【leetcode】Sum Root to leaf Numbers,简单的二叉树的先根遍历模板的应用classSolution:#@paramroot,atreenode#@returnanintegerdefhehe(self,num,root):#再原来的基础上*10。再加上当前的root.val...
[Leetcode][python]Sum Root to Leaf Numbers,题目大意一棵树的每个节点都是0-9中的某一个数字,现在把从根节点到某一个叶子节点之间所有节点的数字依次连接起来组成一个新的数字。要求所有从根节点到叶子节点组成的数字的和。解题思路DFS,到了新的叶子节点就将preSum*10+r
题目链接:Path Sum II | LeetCode OJ Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum. For example: Given the below binary tree and sum = 22, 5 /\ 48 //\ 11134 /\/\ ...
Can you solve this real interview question? Sum Root to Leaf Numbers - You are given the root of a binary tree containing digits from 0 to 9 only. Each root-to-leaf path in the tree represents a number. * For example, the root-to-leaf path 1 -> 2 -> 3
An example is the root-to-leaf path 1->2->3 which represents the number 123. Find the total sum of all root-to-leaf numbers. Note: A leaf is a node with no children. Example: Input: [1,2,3] 1 / 2 3 Output: 25 Explanation: ...
Given the root of a binary tree, return the number of nodes where the value of the node is equal to the sum of the values of its descendants. A descendant of a node x is any node that is on the path from node x to some leaf node. The sum is considered to be 0 if the node ...