(Maths Olympiad 《Odd and Even Numbers》 Pr1&2 Question #15 ) Is the sum of the first 5 even numbers odd or even?相关知识点: 试题来源: 解析 $$$even. 2+4+6+8+10, even + even + even = even The sum of the first 5 even numbers is even.反馈 收藏 ...
百度试题 结果1 题目Is the sum of the first 5 odd numbers odd or even?A.OddB.Even 相关知识点: 试题来源: 解析 A 反馈 收藏
答案解析 查看更多优质解析 解答一 举报 38 2+5+7+11+13=38 解析看不懂?免费查看同类题视频解析查看解答 相似问题 The average (arithmetic mean) of a list of numbers is what percent of the sum of the numbers? The sum of two even numbers is always what? A quarter of the first plus a th...
Submit Find the sum of first 20 even numbers. View Solution What is the sum of first10natural numbers. View Solution View Solution View Solution View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths ...
7 Pairs of Commonly Confused Words What's the difference between 'fascism' and 'socialism'? More Commonly Misspelled Words Words You Always Have to Look Up Your vs. You're: How to Use Them Correctly Popular in Wordplay See All More Words with Remarkable Origins ...
百度试题 结果1 题目Calculate the sum of the first 50 odd numbers 相关知识点: 试题来源: 解析 199=1003+97=100 5+95=100and50on I5 paurs 25×100=2500 反馈 收藏
6, 8 and 10 The sum of the first five even numbers= 2 + 4 + 6 + 8 + 10= 30 5)The difference between the sum of the first five even numbers and 2 = 30 - 2= 28 6)The first odd number following 5 is 7 The quotient = 28 / 7= 4 7)The value of [4+8]÷[5×4-6] ...
Out of 6 numbers, the sum of the first 5 numbers is 7 times the 6th number. If their average is 136, then the 6th number is: 6 संख्याओं में से, पहली 5 संख्
The sum of five consecutive even numbers is equal to 170 . What is the sum of the second largest number amongs them and the squrare of the smallest number amo
This note presents two demonstrations of the known formula for the sum of squares of the first n natural numbers. One demonstration is based on geometrical considerations and the other one uses elementary integral calculus. Both demonstrations are very easy to understand, even for high school ...