n=int(input ()) sum=0 while n%2==0: sum=sum+n n=n-1 print(sum) 19th May 2020, 5:40 PM Satyam Patel 0 Hello everybody! Here is my code using while loop a=int(input()) b=0 c=0 while b<=a: c+=b b+=2 print(c) 21st
Let's try to maintain S, the sum of the array throughout one query operation.When acting on an array element A[index], the rest of the values of A remain the same. Let's remove A[index] from S if it is even, then add A[index] + val back (if it is even.)...
Then the five consecutive even number are n-4, n-2, n, n+2, and n+4. The sum of the five numbers is 5n. Since 5n 320, n=64. Thus n-4, the first number, is 60. 数2,4,6,8是4个连续的偶数,若5个连续的偶数的总和是320,则这五个数中最小的是多少( )? 方法一:奇数个连续数...
Difficulty: (10) Rate Solve Later Add To Group Write a function that takes a vectorxas input and returns the sum of all even numbers inx. Input: x = [1, 2, 3, 4, 5, 6] Output: y = 12 Solve Solution Stats 60.71% Correct | 39.29% Incorrect ...
编写一个Python函数,接收一个整数列表作为参数,返回列表中所有偶数的平均值。```pythondef average_even(numbers):evens = [x for x in numbers if x % 2 == 0]if len(evens) == 0:return 0return sum(evens) / len(evens)numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]print(a
若为偶数,evensum+=A[q[1]] 把evensum放入结果数组res。 代码参考: 1classSolution {2public:3vector<int> sumEvenAfterQueries(vector<int>& A, vector<vector<int>>&queries) {4vector<int>res;5intevensum=0;6for(inta:A){7if(!(a%2))evensum+=a;8}9for(vector<int>q:queries){10if(!(A...
We have an arrayAof integers, and an arrayqueriesof queries. For thei-th queryval = queries[i][0], index = queries[i][1], we addvaltoA[index]. Then, the answer to thei-th query is the sum of the even values ofA. (Here, the givenindex = queries[i][1]is a 0-based index...
简介:Leetcode-Easy 985. Sum of Even Numbers After Queries 题目描述 We have an array A of integers, and an array queries of queries. For the i-th query val = queries[i][0], index = queries[i][1], we add val to A[index]. Then, the answer to the i-th query is the sum of...
9. (a) Calculate the sum of all the even numbers from 2 to 100 inclusive,2+4+6+⋯⋯+100 .(3)(b) In the arithmetic series k+2k+3k+⋯+100 ,k is a positive integer and k is a factor of 100.(i) Find, in terms of k, an expression for the number of terms in this ...
Proof Without Words: Alternating Sum of an Even Number of Triangular NumbersWe provide a visual solution for the alternating sum of an even number of triangular numbers.PlazaMathematics Magazine