1. SPFA算法的四种优化(SLF,LLL,SLF+LLL,DFS)(2) 2. D.Anti-Sudoku 思维题(Codeforces Round #634 (Div. 3))(1) 3. Dijkstra算法优化~~你一定可以看懂的四种进阶优化(1) 4. dijkstra算法详解(迪杰斯特拉算法)简单易懂(1) 最新评论 1. Re:dijkstra算法详解(迪杰斯特拉算法)简单易懂 代码写的真好...
Codeforces_B.Maximum Sum of Digits http://codeforces.com/contest/1060/problem/B 题意:将n拆为a和b,让a+b=n且S(a)+S(b)最大,求最大的S(a)+S(b)。 思路:考虑任意一个数,例如156,将其分为d1:(1,155)或d2:(6,150),其实S(a)+S(b)都是12;但是当分为d3:(7,149)或d4:(9,147)时...
查看题目 登录后递交 讨论 题解 文件 统计 ID 5693 时间 1000ms 内存 256MiB 难度 (无) 标签 dp greedy implementation *1400 递交数 0 已通过 0 上传者 root
Let f(x)f(x) be the sum of digits of a decimal number xx. Find the smallest non-negative integer xx such that f(x)+f(x+1)+⋯+f(x+k)=nf(x)+f(x+1)+⋯+f(x+k)=n. The first line contains one integer tt (1≤t≤1501≤t≤150)— the number of test cases. Each test...
CodeForces - Maximum Sum of Digits Problem Description You are given a positive integer n. Let S(x) be sum of digits in base 10 representation of xx, for example, S(123)=1+2+3=6, S(0)=0. Your task is to find two integers a,ba,b, such that 0≤a,b≤n, a+b=n and S(a...
CodeForces 489C (贪心) Given Length and Sum of Digits...,题意:找出m位且各个数位数字之和为s的最大和最小整数,不包括前导0(比如说003是非法的),但0是可以的。分析:这题是用贪心来做的,同样是m位数,前面的数字越大这个数就越大。所以写一个can(intm,ints)函数,来
sequences, and I had no luck. I've also tried rewriting it in many ways, etc, but I had no luck. I'm guessing you can just stimulate the process, but I'm pretty sure it would be very expensive (especially for large numbers where you need to obtain the kth digit of the number)...
It says to calculate sod(n) [sum of digits of n] while n >= 10. Here n = a^b, (0<= a,b <= 10^50,000 and a+b>0 ) I got the solution idea from this cf post. It can be proven that the repeated digit sum of N is 1 + (N - 1) mod 9, so we basi...
提示: In the first sample the number already is one-digit — Herald can’t cast a spell. The second test contains number 10. After one casting of a spell it bec...
Codeforces Round #513 B. Maximum Sum of Digits(思维) 题目链接:http://codeforces.com/contest/1060/problem/B 题意是输入一个n,从1-n中找两个数,使得a+b=n,而且S(a)+S(b)的值是所有两个数中最大的...思路算是贪心吧,为了让S(a)+S(b)的值最大,所以我们要让a里尽量多的包含9,这样就能求...