importjava.util.Scanner;publicclassSumOfDigits{//Method to calculate thesumof digits using awhileloop public staticintcalculateSum(intnumber){intsum=0;//Loop until the number becomes0while(number!=0){sum+=number%10;//Add the last digit tosumnumber=number/10;//Remove the last digit}returnsu...
in); System.out.print("Enter A Number : "); num =sl.nextInt(); while(num >0) { r=num %10; sum=sum+r; num =num/10; } System.out.println("The Sum of Digit is : "+ sum); } }You’ll also like: Sum of Digits of a Number in Java Example C Program Sum of Digits of...
One of the common programming practice question thrown to beginners is to write a program to calculate the sum of digits in an integral number. For example, if the input is 123456 then output or sum of the digit is (1+2+3+4+5+6) = 21. An additional condition is you can not use ...
In the first sample the number already is one-digit − Herald can't cast a spell. The second test contains number10. After one casting of a spell it becomes1, and here the process is completed. Thus, Gerald can only cast the spell once. The third test contains number991. As one ca...
In this post, we will see how to find sum of digits of number in java. You can find unit’s place digit by number%10, add it to the total and divide the number by 10 to remove the unit’s place. 1 2 3 4 5 6 7 8
import java.util.*; public class SumTheDigitsInAnIntegerQuestion2 { public static void main(String[] args) { long number; Scanner inputScanner = new Scanner(System.in); System.out.print("Enter an integer:"); number = inputScanner.nextLong(); ...
[LeetCode] 1837. Sum of Digits in Base K Given an integern(in base10) and a basek, returnthe sum of the digits ofnafter convertingnfrom base10to basek. After converting, each digit should be interpreted as a base10number, and the sum should be returned in base10....
It then removes the last digit from 'n' by dividing it by 10 (n /= 10). This process continues until all digits of the original number have been processed. Finally, it returns the 'sum' containing the sum of the digits. Finally, back in the "main()" method, it prints the result...
assertEquals(-47,SumOfDigitSolution.sumOfDigit(Integer.MIN_VALUE)); } } That's all abouthow to solve this coding problem ofcalculating the sum of digits in a given number using recursion in Java. Though recursion has several drawbacks like hard to read, write and StackOverflow error, there...
Given an integer number n, return the difference between the product of its digits and the sum of its digits. Example 1: Input: n = 234 Output: 15 Explanation: Product of digits = 2 * 3 * 4 = 24 Sum of digits = 2 + 3 + 4 = 9 Result = 24 - 9 = 15 ...