Codeforces 920 F SUM and REPLACE Dicription Let D(x) be the number of positive divisors of a positive integer x. For example, D(2) = 2 (2 is divisible by 1 and 2), D(6) = 4 (6 is divisible by 1, 2, 3
#include<bits/stdc++.h>usingnamespacestd;constintMAXN = 3e5 +10;constintMAXP = 1e6 +10; typedeflonglongll; typedeflongdoubleld;intn , m;intval[MAXN] , p[MAXP]; template<typename T> inlinevoidchkmax(T &x,T y) { x =max(x,y); } template<typename T> inlinevoidchkmin(T &x...
Codeforces 920F - SUM and REPLACE 【线段树】 题目链接> 题目大意: 给你一个序列,有两个操作,一个是求区间 l - r 的和,另一个是对区间l-r的元素修改值,x=d(x),d(x)为x的因子个数。 解题分析: 因为可能有多次修改操作,并且修改的范围可能比较大,所以提前将1~1e6范围内的数的因子个数全部打表进行...
Codeforces 920F SUM and REPLACE-线段树+欧拉筛 传送门 题意: n个数a,q个操作,两种操作类型: 1.[l,r]区间中每个数替换为这个数的因数个数 2.区间求和 q,n<=3e5,ai<=1e6 q , n <= 3 e 5 , a i <= 1 e 6 Solution: 值为1或2的数是不需要再进行操作的 对于每个线段树节点所代表的区间...
[线段树] CodeForces - 920F SUM and REPLACE (数学优化) https://vjudge.net/problem/1349242/origin 题意:给出一个数组,有两个操作,一个操作把区间所有数都变成其因子个数,另一个操作询问区间和。 一个树的约束个数 最多 2∗sqrt(n)2*sqrt(n)2∗sqrt(n) 我每次 变成它的约束...Codeforces...
Codeforces 920 F SUM and REPLACE Dicription LetD(x) be the number of positive divisors of a positive integerx. For example,D(2) = 2 (2 is divisible by 1 and 2),D(6) = 4 (6 is divisible by 1, 2, 3 and 6).
你需要额外用一个set来维护哪些值是还能变化的。 然后在读入l,r这个范围的时候。 直接用lower_bound查找离它最近的且大于等于它的能改变的值。 将它改变。 然后在树状数组中改变对应位置的值。 如果发现改变之后这个数字变成小于等于2了。 那么就在set中删掉这个值。
In other words, no more than k times you are allowed to take an arbitrary number ai from the array and replace it with - ai. Each number of the array is allowed to choose an arbitrary number of times. Your task is to calculate the maximum possible optimal sum of the array ...
SUM and REPLACE【线段树】 Let D(x) be the number of positive divisors of a positive integer x. For example, D(2) = 2 (2 is divisible by 1 and 2), D(6) =&th...Educational Codeforces Round 38 F. Erasing Substrings DP Description 给你一个长度为n的串,K次操作(K=⌊...
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