时间复杂度:假设 s 的长度是 n,words 里有 m 个单词,那么时间复杂度就是 O(n * m)。 空间复杂度:两个 HashMap,假设 words 里有 m 个单词,就是 O(m)。 解法二 参考https://leetcode.com/problems/substring-with-concatenation-of-all-words/discuss/13656/An-O(N)-solution-with-detailed-explanation。
You are given a string, s, and a list of words, words, that are all of the same length. Find all starting indices of substring(s) in s that is a concatenation of each word in words exactly once and without any intervening characters. 难度:Hard 2 题目样例 For example, given:s: "ba...
You are given a string,s, and a list of words,words, that are all of the same length. Find all starting indices of substring(s) insthat is a concatenation of each word inwordsexactly once and without any intervening characters. For example, given: s:"barfoothefoobarman" words:["foo",...
Substring with Concatenation of All Words 题解 题意 You are given a string, s, and a list of words, words, that are all of the same length. Find all starting indices of substring(s) in s that is a concatenation of each word in words exactly once and without any intervening characters...
参考https://leetcode.com/problems/substring-with-concatenation-of-all-words/discuss/13656/An-O(N)-solution-with-detailed-explanation。 我们在解法一中,每次移动一个字符。 现在为了方便讨论,我们每次移动一个单词的长度,也就是 3 个字符,这样所有的移动被分成了三类。
You are given a string, s, and a list of words, words,that are all of the same length. Find all starting indices of substring(s) in s that is a concatenation of each word in words exactly once and without any intervening characters. ...
You are given a string, S, and a list of words, L, that are all of the same length. Find all starting indices of substring(s) in S that is a concatenation of each word in L exactly once and without any intervening characters. ...
Leetcode: Substring with Concatenation of All Words You are given a string, S, and a list of words, L, that are all of the same length. Find all starting indices of substring(s) in S that is a concatenation of each word in L exactly once and without any intervening characters....
Create 030SubstringWithConcatenationOfAllWords.md Aug 24, 2018 1 #[Substring with Concatenation of All Words][title] 2 3 ##Description 4 5 You are given a string,**s**, and a list of words,**words**, that are all of the same length. Find all starting indices of substring(s)...
For example, ifwords = ["ab","cd","ef"], then"abcdef","abefcd","cdabef","cdefab","efabcd", and"efcdab"are all concatenated strings."acdbef"is not a concatenated substring because it is not the concatenation of any permutation ofwords. ...