}*///正确:stringfind(stringMainWord,set<string, length_more>WordPool) {set<string>::iterator it;stringres ="";for(it = WordPool.begin(); it != WordPool.end(); ++it) {inti =0;stringword = *it;boolflag =false;for(intj =0; j < word.length(); ++j) { flag=false;for(;i <...
48 changes: 48 additions & 0 deletions 48 Subsequence_Bitmasking/subsequence_bitmasking.cpp Original file line numberDiff line numberDiff line change @@ -0,0 +1,48 @@ //Subsequence of a String using bitmasking #include<iostream> #include<string>...
Parse a string-serialized MultiSlice object. nodejs javascript node parse stdlib convert range slice ndarray node-js sequence base subsequence subseq Updated Dec 20, 2024 JavaScript CodeRex7 / CodingPractice Star 1 Code Issues Pull requests avl-tree stack queue cpp14 priority-queue bit-manipul...
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace" is a subsequence of "abcde" while "aec" is not). Example 1: s = "abc...
cpp 直接按s串的顺序去遍历t串即可。 class Solution { public: bool isSubsequence(string s, string t) { int i = 0, j = 0; while(i<s.length() && j < t.length()) { if(s[i] == t[j]) { i++; } j++; } return i == s.length(); } }; 查看更多 赞同 0 添加评论2020-06...
The first line contains only one integer T (T<=50), which is the number of test cases. Each test case contains a string S, the length of S is not greater than 1000 and only contains lowercase letters. Output For each test case, output the case number first, then output the number ...
所以,代码如下: 代码语言:javascript 复制 intfindLUSlength(string a,string b){int s1=a.size(),s2=b.size();if(s1!=s2)returnmax(s1,s2);elseif(a!=b)returns1;elsereturn-1;} 实测3ms,beats 96.79% of cpp submissions。
leetcode 516 Longest Palindromic Subsequence 先看一下题目原文: Given a string s, find the longest palindromic subsequence’s length in s. You may assume that the maximum length of s is 1000. Example 1: I... 查看原文 LeetCode516.最长回文子序列 ...
public class Solution { /** * @param S: a string * @param T: a string * @return: the minimum substring of S */ public String minWindow(String s, String t) { int m = s.length(); int n = t.length(); int start = -1; int minLen = Integer.MAX_VALUE; //dp 方程,s中前M...
import pylcs # finding the longest common subsequence length of string A and string B A = 'We are shannonai' B = 'We like shannonai' pylcs.lcs_sequence_length(A, B) """ >>> pylcs.lcs_sequence_length(A, B) 14 """ # finding alignment from string A to B A = 'We are shanno...