在VBA编程中,“subscript out of range”错误是一个常见的运行时错误,通常发生在尝试访问不存在的数组元素或对象属性时。下面我将按照你的提示,详细解释这一错误。 1. “subscript out of range”错误的含义 “subscript out of range”错误意味着你尝试访问的数组元素或对象属性超出了其定义的范围。在VBA中,数组...
try: value = array[index] except IndexError: value = None 动态获取数据长度 避免固定循环次数,改用for element in array或for i in range(len(array))。启用调试工具 使用IDE的调试功能(如断点、变量监视)实时跟踪索引和数据长度变化。实际案例(以Excel VBA为例)问题代码:...
问第二次运行VBA代码时出现"Subscript out of Range“错误ENPython中包含错误和异常两种情况①，错误主要...
You referenced a nonexistent array element. The subscript may be larger or smaller than the range of possible subscripts, or the array may not have dimensions assigned at this point in the application. Check thedeclarationof the array to verify its upper and lower bounds. Use theUBoundandLBou...
Error message: 'Subscript out of range' occurs when using LBound() or UBound() on a VBA array, Dynamic Array Implementation in Visual Basic Scripting, VBScript and the Use of Zero-length Arrays, Understanding the Purpose and Function of LBound in VBScrip
calltime) = Price(i) - Price(i - 1) Case ma(i) < Price(i) And ma(i - 1) < Price(i - 1) pprofit(puttime) = Price(i - 1) - Price(i) End SelectNext iReDim cprofit(calltime) As Single, pprofit(puttime) As SingleEnd Sub 名字为sheet1的工作薄不存在...
I have been troubled with a subscript out of range issue. At the very least I am looking to be able to address an array of arrays, apparently called a jagged array. I have a simple example (chatGPT... peiyezhu Bronze Contributor ...
I have been troubled with a subscript out of range issue. At the very least I am looking to be able to address an array of arrays, apparently called a jagged array. I have a simple example (chatGPT) that works wonderfully and when I look at the structure of arr_fi...
And that’s the mistake we have made in the above code and VBA has returned the “Script Out of Range” error. Sub myMacro() Dim myArray() As Variant myArray(1) = "One" End Sub Wrong Range Reference In below code, if “ZZ100” refers to a cell outside the existing columns in ...
Sheets(1).SelectvSheetName = ActiveSheet.Name'获取要打开工作簿名称tBookName = ThisWorkbook.Sheets(1).Range("D6") & ".xls"tPath = ThisWorkbook.Sheets(1).Range("D7")'获取当前工作簿路径If tPath = "" Or tPath = "\" ThenFilePath = ActiveWorkbook.Path & "\" & tBookNameElse...