This is the complete query I am using below. Hbm_Matter will only 1 have unique record(matter_uno). How do I get multiple records returned in my query when there are 2 records in the subquery? select matter_uno, matter_name, bill_empl_uno from hbm_matter a where exists ( select top...
select_statement:必填。子查询语句。格式请参见SELECT语法。 sq_alias_name:可选。子查询的别名。 table_name:必填。目标表名称。 使用示例 示例1:子查询语法的命令示例如下。 set odps.sql.allow.fullscan=true; select * from (select shop_name from sale_detail) a; 返回结果如下: +---+ | shop_name...
where A.ID not in (SelectTop(30)AkteID from RW_RECH) " gives me a result which I expect. Is there any way to make the first SQL command work correctly? I get an empty result. This isnot expectedand thereforeincorrect. schumifrick, the empty resultis expectedand ther...
in => = any(...) i > all() => not(i <= any(...)) some => any 子查询几乎可以出现在 SQL 的任何位置,如 from/where/select/group by/having/order by, 外加关联子查询的存在,所以处理子查询变得具有挑战性,在深入子查询之前,先介绍一下 Databend 为了高效处理子查询 而引入的非标准 join ...
sql sql-server tsql logic 我正在尝试运行以下查询,但遇到此错误: 无法对包含聚合或子查询的表达式执行聚合函数。 SELECT IVCSUM1.ivcnum "Invoice Number" ,IVCSUM1.ivcgrsamt_amt "Gross Amount" ,IVCSUM1.ivcgrsamt_cur "Gross Amount Currency" ,SUM(ISNULL(IVCLINE1.ivclinextamt_amt, 0) + ISNULL...
A second SELECT statement ( Subquery (subquery)) can be included in a SELECT statement. A value or set of values is generated by the Subquery as part of the main statement. Prerequisites You can use the demo data for the SQL tutorial. Start the Database Studio as database administrator MO...
This statement is used to embed a subquery in the HAVING clause. The subquery result is used as a part of the HAVING clause.All is used to return repeated rows. By defaul
sql_cond - subquery Syntax ... ( SELECT{select_clause FROMsource} |{FROMsource FIELDSselect_clause} [WHEREsql_cond] [GROUP BYgroup][HAVINGgroup_cond] [UNION[ALL|DISTINCT]select]) ... Effect Asubqueryof theWHEREcondition is a parenthesizedSELECTstatement in which all additions exceptSINGLE,...
SELECT TO_CHAR(MAX(SUM(salary))) Max_Salary FROM teams t JOIN playersalary p ON t.id = p.team_id GROUP BY name; Output: 在这里我可以拿到最高工资,但我不能显示球队的名字。 #2: SELECT name, salary FROM teams t JOIN playersalary p ON t.id = p.team_id ...
the subquery is not introduced with EXISTS. Solution / Work Around : One way to avoid this error is to follow the suggestion of the error message and provide only one expression, or one column, in the SELECT subquery statement. SELECT [OrderHeaderID], [OrderDate], [OrderDescription], [Tot...