Given pre_xor the ideal value to xor it with is one that has 0s where pre_xor has 1s and viceversa. The trie helps in finding the value that comes closest to the optimal one among f(0, l-1) for all 0 <= l <= i.
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intn) {12for(inti =0; i < n; i++) {13if(arr[i] >0)returnfalse;14}15returntrue;16}1718intmaxsum(intarr[],intn) {19inttmp =0;20intans =INT_MIN;21for(inti =0; i