1 class Solution { 2 public int minSubArrayLen(int s, int[] nums) { 3 if (nums == null || nums.length == 0) { 4 return 0; 5 } 6 int N = nums.length; 7 int min = Integer.MAX_VALUE; 8 int left = 0; 9 int sum = 0; 10 11 for(int i = 0; i < N; i++) { ...
Java for LeetCode 209 Minimum Size Subarray Sum Given an array ofnpositive integers and a positive integers, find the minimal length of a subarray of which the sum ≥s. If there isn't one, return 0 instead. For example, given the array[2,3,1,2,4,3]ands = 7, the subarray[4,3]h...
import java.util.HashMap; class Solution { public int subarraySum(int[] nums, int k) { HashMap<Integer,Integer> prefixSum = new HashMap<>(); prefixSum.put(0,1); int sum = 0, count = 0; for(int i=0; i<nums.length; i++){ sum = sum + nums[i]; int curr = prefixSum.ge...
The length of the array won't exceed 10,000. You may assume the sum of all the numbers is in the range of a signed 32-bit integer. Solution class Solution { public boolean checkSubarraySum(int[] nums, int k) { if (nums == null || nums.length < 2) return false; if (k == ...
Check if contains a subarray that sum up equals to times of k and pay attention: all elements in given array are non-negative. this problem is pretty easy, still, I stucked on conner case which k==0 f...LeetCode 523. Continuous Subarray Sum 题目: Given a list of non-negative numbe...
560. 和为K的子数组(Subarray Sum Equals K) 560. 和为K的子数组(Subarray Sum Equals K) 题解 哈希 复杂度分析 Python Java(待完成)题解借助哈希表保存累加和sumsum及出现的次数。若累加和sum−ksum−k在哈希表中存在,则说明存在连续序列使得和为kk。则之前的累加和中,sum−ksum−k出现的次数即...
这个问题是这样的(https://leetcode.com/problems/maximum-subarray/): Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. 就是给一组整数,找到一组连续的子序列,让子序列的和最大,并且返回最大和。 比如说: 输入...
You may assume the sum of all the numbers is in the range of a signed 32-bit integer. 思路: 因为是非负数,遍历数组一遍一直加,并且记录mod k的结果,只要出现过,判断一下位置即可返回结果。 class Solution { public boolean checkSubarraySum(int[] nums, int k) { ...
题目: Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exa... leetcode之Combination Sum III 问题 ...
size()); int sum = 0; for (int i = 0; i < numsSize; i++) { sum += nums[i]; result = max(result, sum); //如果sum < 0,重新开始找子序串 if (sum < 0) { sum = 0; } } return result; } }; 作者:pinku-2 链接:https://leetcode-cn.com/problems/maximum-subarray/...