See the following code. import java.util.Arrays; public class Main { public static void main(String[] args) { int a[] = {3, 5, 8, 4, 6, 7}; int[] b = Arrays.copyOfRange(a, 2, 4); for (int i : b) System.out.print(i + " "); } } Output: 8 4 Use the array...
java代码如下: 1publicclassSolution {2publicintmaxSubArray(int[] A) {3intsum=A[0],tmp=A[0];4for(inti=1;i<A.length;i++){5if(tmp>0){6tmp+=A[i];7}8else{9tmp=A[i];10}11if(tmp>sum){12sum=tmp;13}14}15returnsum;16}17} python代码如下: 1classSolution:2#@param A, a list...
publicclassSolution {publicintmaxProduct(int[] nums) {intlen =nums.length;if( nums.length == 1)returnnums[0];int[] result =newint[2];inttarget = 0;intleft_right = 0,right_left = 0;for(inti = 0 ; i < len ; i ++){if( nums[i] == 0){ target= Math.max(target,result[0]...
[leetcode] 581. Shortest Unsorted Continuous Subarray 题目: Given an integer array, you need to find one continuous subarray that if you only sort this subarray in ascending order, then the whole array will be sorted in ascending order, too. You ......
The following Java example demonstrates to create anArrayListfrom a subarray. It is done in two steps: Create a subarray from the array with desired items. Convert array toList. String[]names={"Alex","Brian","Charles","David"};//Array to sublistList<String>namesList=Arrays.asList(Arrays....
[leetcode]718. Maximum Length of Repeated Subarray [leetcode]718. Maximum Length of Repeated Subarray Analysis 今天被微博上的孙艺兴bot笑死,哈哈哈哈哈—— [每天刷题并不难0.0] Given two integer arrays A and B, return the maximum length of an subarray that appears in ......
Learn various approaches to find a subarray with a given sum in Java, including step-by-step explanations and code examples.
Example: to access the value 4 in the second subarray, we can use the below code: console.log(array[1][1]); Output 4 We can also use array methods like map, reduce, forEach and many others to iterate through elements of subarrays...
代码语言:javascript 代码运行次数:0 publicbooleancheckSubarraySum(int[]nums,int k){Map<Integer,Integer>map=newHashMap<Integer,Integer>();map.put(0,-1);//为了处理nums=[0,0] k=-1这样的情况int sum=0;for(int i=0;i<nums.length;i++){sum+=nums[i];if(k!=0)sum%=k;Integer prev=map...
leetcode974. Subarray Sums Divisible by K Given an array A of integers, return the number of (contiguous, non-empty) subarrays that have a sum divisible by K. Example 1: Note: 给定一个集合,求这个集合中子集的个数,其中对子集的要求是子集中元素的和能被k整除。 记数组pre[i+1]表示前 i ...