There are a lot of possible ways to organize a Node.js project - and each of the known methods has their ups and downs. However, according to our experience, developers always want to achieve the same things: clean code and the possibility of adding new features with ease. In the past ...
对于遗留项目,一般业务已经非常稳定,但新人刚加入团队,面对几百张表的业务系统往往摸不到头脑。有了DrawERD,新人可以快速的了解项目数据关系,对应用有系统性的认识。 如果你的数据库已经有几百张表,打算从单体应用向微服务迁移,那么DrawERD的分组功能是一个最佳工具,通过对模块的分组模拟,你可以清晰的判断哪个实体放到...
node.js express After using node.js / express.js in some projects, I have found Kraken's (1.+) structure very useful. It uses folders as part of the routes. Also, it comes with a scaffolding tool, so the mvc structure is easy to keep. This is not the only solution, but it is ...
一、后端服务nodejs,thinjs的redis配置,操作数据库 我使用的是thinkjs,一个nodejs的框架。 1、首先介绍登陆的控制 逻辑: (1)已经登陆的,直接根据的路由跳到相应页面; (2)已经登陆的,不能跳到登陆页面,跳到首页; (3)没有登陆的,输入url必须跳到登陆页; ...
It's tool that helps to visualize current state of your project. It's really easy to see how tight your classes are coupled. javascript swift objective-c graph structure dependency-graph dependency dependency-tree d3js swift-dependencies-visualizer Updated Apr 28, 2020 JavaScript ...
Angular官方给的Demo,拿到本地后编译不过,提示node_modules/rxjs/Rx"' has no exported member 'of' 发现在引用OF的时候Demo给的是 没深究原理,不过不论是在线Demo还是下载下来的都是编译错误,所以还原了这个引用方式,用之前的Step中的引用方式,问题解决,附图 ...
Sets theweight(a number) of the edge from nodeuto nodev. #graph.getEdgeWeight(u,v) Gets theweightof the edge from nodeuto nodev. If no weight was previously set on this edge, then the value 1 is returned. Querying the Graph
('.dx-treeview-node'); const isDragIntoChild = $nodes.eq(e.fromIndex).find($nodes.eq(e.toIndex)).length > 0; if (isDragIntoChild) { e.cancel = true; } } }, onDragEnd(e) { if (e.fromComponent === e.toComponent && e.fromIndex === e.toIndex) { return...
Node.js tutorial for Data Structure List of Node.js tutorial under Data Structure HOME Node.js Data Structure DescriptionThe tutorials for Node.js Data Structure are organized in the following topics. The topics of Data Structure are organized into 1 topic(s)....
{ this.children.push(child); } else { throw new Error('That child is already a child of this tree'); } // return the new child node for convenience return child; }; /** * check to see if the provided tree is already a child of this * tree __or any of its sub trees__ *...