STRING_AGG([dbo].[HashTable].[Hash] as [HT1].[Hash],'') WITHIN GROUP (ORDER BY [HT2].[Hash]) Run Code Online (Sandbox Code Playgroud) 如果您是sysadmin,则可以使用以下未记录的 来为查询关闭此规则OPTION。 <OrderBy> <OrderByColumn Ascending="1"> <ColumnReference Database="[...]"...
I am not sure if has something to do with outsystems built in database engine that utilizes a different syntax for this purpose or if has something to do with database versions also possibly affecting the syntax. I also tried to run SELECT STRING_AGG ({CONTRAPARTES}.[Nome], '...
示例:SELECT department, COUNT(DISTINCT employee_id) AS employee_count FROM employees GROUP BY department WITH ROLLUP; 结果为每个部门的员工数量,包括总的员工数量和每个部门的详细信息 三、使用场景 string_agg方法在处理数据列表时非常有用,以下是几个常见的使用场景: 1. 连接字符串:将一系列值连接成单个字符...
order by可以任意字段、表达式、类型转换 selectgid, string_agg(val,','orderbyxx::numeric)fromtbl1groupbygid;selectgid, string_agg(val,','orderbyabs(xxx))fromtbl1groupbygid;selectgid, string_agg(val,','orderbymod(x,5),xxxx)fromtbl1groupbygid; postgres=#createtabletbl(idint, c1text);CREAT...
<order_clause>is available with database compatibility level 110 and above. Examples Most of the examples in this article reference theAdventureWorks sample databases. A. Generate list of names separated in new lines The following example produces a list of names in a single result cell, separated...
如果你不想创建临时表，把拆分的数据插⼊临时表，步骤繁复。可以使⽤派⽣表来进⾏：SELECT STRING_AGG([value], ',') WITHIN GROUP (ORDER BY[value])FROM (SELECT[value]FROM STRING_SPLIT(@str,',')) source Source Code 或者使⽤⼀般资料表运算式CTE (Common Table Expression);WITH dump_...
sql STRING_AGG 作用优先级,withfas(select*fromUNNEST([1,3,8,9,13,23,5,4,23,55,77,6])asfruit)SELECT*,STRING_AGG(cast(fruitasstring),",")OVER(ORDERBYfruitROWSBETWEEN0FOLLOWINGAND3FOLLOWING)asclick_historyFROMfwherefruit>4;STRING_AGG的.
The following example replaces null values with 'N/A' and returns the names separated by commas in a single result cell. SQL USEAdventureWorks2022; GOSELECTSTRING_AGG(CONVERT(NVARCHAR(MAX),ISNULL(FirstName,'N/A')),',')AScsvFROMPerson.Person; GO ...
SELECTdepartment_id,string_agg(employee_name,'/'ORDERBYemployee_id)ASemployee_namesFROMemployeesGROUPBYdepartment_idORDERBYdepartment_id; 参考リンク postgresql - How to get result from string_agg() with a proper order by - Stack Overflow
BY FieldA ORDER BY FieldA;SQLServer≤2016(包括cte以鼓励干原理) WITH CTE_TableName AS (