我们可以通过Stream的map()方法将String列表中的每个元素都转化为int类型。下面是示例代码: List<String>strList=Arrays.asList("1","2","3","4","5");List<Integer>intList=strList.stream().map(Integer::parseInt).collect(Collectors.toList());System.out.println(intList); 1. 2. 3. 4. 5. 6...
importjava.util.ArrayList;importjava.util.List;publicclassStringToIntListConverter{publicstaticList<Integer>convert(String[]stringArray){List<Integer>intList=newArrayList<>();for(Strings:stringArray){intList.add(Integer.parseInt(s));}returnintList;}publicstaticvoidmain(String[]args){String[]stringArray...
String[] split=characterIds.split(",");int[] ints=Arrays.asList(split).stream().mapToInt(Integer::parseInt).toArray(); List<Integer>collect=Arrays.stream(ints).boxed().collect(Collectors.toList());
Stringids="1,2,3,4,5"; List<Integer>idList=Arrays.stream(ids.split(",")).map(Integer::parseInt).collect(Collectors.toList()); 集合或数组转变为逗号分隔的字符串的几种方式 首先,创建一个集合 List<String>list=Lists.newArrayList(null,"bob","jack"); 1、自己编码实现 publicstatic<T>Stringjoin...
观察是否将列表和非列表的类型相连。观察是否将列表和非列表的类型相连。观察是否将列表和非列表的类型...
class}) public class ListTypeHandler extends BaseTypeHandler<List<String>> { private static final String DELIM = ","; @Override public void setNonNullParameter(PreparedStatement preparedStatement, int i, List<String> strings, JdbcType jdbcType) throws SQLException { String value = StringUtils.collection...
//请参考：string a = "1,2,3,4,5";List<int> list = a.Split(new string[] { "," }, StringSplitOptions.RemoveEmptyEntries).Cast<int>().ToList<int>();//欢迎追问。
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string strIDs = "15|20|30"; List<int> IDs; string[] strArr = strIDs.Split('|'); int[] intArr = Array.ConvertAll<string, int>(strArr, new Converter<string, int>(Convert.ToInt32)); IDs = intArr.ToList(); Tuesday, October 28, 2008 5:58 PM ✅AnsweredUsing...
我有一个字符串: String ints = "1, 2, 3"; 我想将其转换为整数列表: List<Integer> intList 我可以通过这种方式将其转换为字符串列表: List<String> list = Stream.of("1, 2, 3").collect(Collectors.toList()); 但不要列出整数。 有任何想法吗?