# Program to check if a string is palindrome or not my_str = 'aIbohPhoBiA' # make it suitable for caseless comparison my_str = my_str.casefold() # reverse the string rev_str = reversed(my_str) # check if the st
Palindrome Check Using String Slicing # Python program to check if a string is# palindrome or not# function to check palindrome stringdefisPalindrome(string):rev_string=string[::-1]returnstring==rev_string# Main codex="Google"ifisPalindrome(x):print(x,"is a palindrome string")else:print(x,...
This is a Python Program to check whether a string is a palindrome or not using recursion. Problem Description The program takes a string and checks whether a string is a palindrome or not using recursion. Problem Solution 1. Take a string from the user. 2. Pass the string as an ...
Python | Check if a variable is a string To check whether a defined variable is a string type or not, we can use two functions which are Python library functions, Using isinstance() Using type() Checking a variable is a string or not using isinstance() function ...
综合以上步骤,完整的 is_palindrome 函数代码如下: python def is_palindrome(string): reversed_string = string[::-1] if string == reversed_string: return True else: return False 这个函数可以检查任何给定的字符串是否为回文。例如: python print(is_palindrome("racecar")) # 输出: True print(is_...
Python Program to Check a String and Number is Palindrome Or Not $emptyString = ""; if ($emptyString =~ /^\s*$/) { print "String is empty and length is zero\n"; } #Conclusion In summary, various approaches are utilized: Length Function: The length function is easy to use and ...
Write a Kotlin function that checks if a string is a palindrome or not.Pre-Knowledge (Before you start!)Basic Kotlin Syntax. Kotlin Functions. String Manipulation. Regular Expressions. Conditional Logic. Printing Output.Hints (Try before looking at the solution!)...
Check Palindrome in Python Using List Slicing Example # Enter stringword=input()# Check for palindrome strings using list slicingifstr(word)==str(word)[::-1]:print("Palindrome")else:print("Not Palindrome") The program begins by prompting the user to input a string using theinput()function...
class Solution: def removePalindromeSub(self, s: str) -> int: return 1 if s == s[::-1] else 2 1. 2. 3. 1347. 制造字母异位词的最小步骤数 Leetcode class Solution: def minSteps(self, s: str, t: str) -> int: x = Counter(s) for ch in t: x[ch] -= 1 return sum(v ...
def is_palindrome(word): return word.lower() == word.lower()[::-1] def task(string): words = string.split(' ') returned = dict() i = 0 while i < len(words): if is_palindrome(words[i]): # if palindrome returned[words[i]] = [] j = i + 1 while j < len(words) and ...