defcount_substring(string,sub_string):count=0;foriinrange(len(sub_string),len(string)+1):if(string[i-len(sub_string):i]==sub_string):count+=1returncount count_substring():=0foriinrange(0,len(string)):if(string[i:i+len(sub_string)]==sub_string):count+=1print(count)s=input()s...
defcount_substring(string,sub_string):count=0foriinrange(len(string)-len(sub_string)+1):if(string[i:i+len(sub_string)]==sub_string):count+=1returncount like mine defcount_substring(string,sub_string):counter=0sub_len=len(sub_string)foriinrange(0,len(string)):ifstring[i]==sub_stri...
Find a string check this def count_substring(string, sub_string): count =0 for i in range(0,len(string)-len(sub_string)+1): try: if string[i:i+len(sub_string)]==sub_string: count+=1 except IndexError: break return count
count = 0 for i in range(0,len(string)-len(sub_string)+2): if (string[i:i+len(sub_string)]==sub_string): count=count+1