char destination[sizeof(source)]; 2. 忘记添加终止字符 (Forgetting to Add Null Terminator) 确保源字符串以\0结尾是非常重要的。如果源字符串不是以\0结尾,strcpy将无法正确复制字符串。检查源字符串的定义,确保它是一个有效的C字符串。 3. 使用未初始化的目标数组 (Using Uninitialized Destination Array) ...
1)Copies the null-terminated byte string pointed to bysrc, including the null terminator, to the character array whose first element is pointed to bydest. The behavior is undefined if thedestarray is not large enough. The behavior is undefined if the strings overlap. The behavior is undefined...
h> int main(void) { char src[] = "hi"; char dest[6] = "abcdef"; // no null terminator strncpy(dest, src, 5); // writes five characters 'h', 'i', '\0', '\0', '\0' to dest printf("strncpy(dest, src, 5) to a 6-byte dest gives : "); for(size_t n = 0; ...
#define __STDC_WANT_LIB_EXT1__1#include<string.h>#include<stdio.h>#include<stdlib.h>intmain(void){char*src="Take the test.";// src[0] = 'M' ; // this would be undefined behaviorchar dst[strlen(src)+1];// +1 to accomodate for the null terminatorstrcpy(dst,src);dst[0]='...
Copies the null-terminated byte string pointed to by src, includingthe null terminator, to the character array whose first element ispointed to by dest. The behavior is undefined if the dest array isnot large enough. The behavior is undefined if the strings overlap.The behavior is undefined if...
strcpy使用中有哪些安全风险Copyright © Yisu Cloud Ltd. All Rights Reserved. 2018 版权所有 ...
If you can guarantee that the destination string has enough space to hold the source string including its null-terminator, just use strcpy() and ignore the compiling warning; if the compiling warning is carking, suppress it with #define _CRT_SECURE_NO_WARNINGS ...
关于char *strcpy( char *dest, const char *src );,去看一下cppreference里的描述:Copies the null-terminated byte string pointed to by src, includingthe null terminator, to the character array whose first element ispointed to by dest. The behavior is undefined if the dest array isnot large ...
Run this code #include <iostream>#include <cstring>#include <memory>intmain(){constchar*src="Take the test.";// src[0] = 'M'; // can't modify string literalautodst=std::make_unique<char[]>(std::strlen(src)+1);// +1 for the null terminatorstd::strcpy(dst.get(), src);dst...
#include<string.h>intmain(){charsource[]="Hello, World!";chardestination[20];strcpy(destination,source);printf("The result of copied string: %s\n",destination);return0;} Output The above code produces the following output − The result of copied string: Hello, World!