https://github.com/grandyang/leetcode/issues/1140 类似题目: Stone Game 参考资料: https://leetcode.com/problems/stone-game-ii/ https://leetcode.com/problems/stone-game-ii/discuss/345247/C%2B%2B-DP-(Tabulation) https://leetcode.com/problems/stone-game-ii/discuss/345230/JavaPython-DP-Soluti...
class Solution{public:intstoneGameII(vector<int>&piles){intn=piles.size(),sum=0;vector<vector<int>>dp(n,vector<int>(n+1));for(inti=n-1;i>-1;i--){sum+=piles[i];for(intj=1;j<=n;j++){if(i+(j<<1)>=n)dp[i][j]=sum;elsefor(intk=1;k<=(j<<1);k++)dp[i][j]=m...
原题链接在这里:https://leetcode.com/problems/stone-game-ii/ 题目: Alex and Lee continue their games with piles of stones. There are a number of piles arranged in a row, and each pile has a positive integer number of stonespiles[i]. The objective of the game is to end with the most...
Can you solve this real interview question? Stone Game II - Alice and Bob continue their games with piles of stones. There are a number of piles arranged in a row, and each pile has a positive integer number of stones piles[i]. The objective of the game
/** @lc app=leetcodeid=1140 lang=cpp** [1140] Stone Game II** https://leetcode.com/problems/stone-game-ii/description/**algorithms* Medium (60.44%)* Likes: 121* Dislikes: 27* Total Accepted: 4.5K* Total Submissions: 7.5K* Testcase Example: '[2,7,9,4,4]'** Alex and Lee con...
1049 Last Stone Weight II 最后一块石头的重量 II Description: You are given an array of integers stones where stones[i] is the weight of the ith stone. We are playing a game with the stones. On each turn, we choose any two stones and smash them together. Suppose the stones have weight...
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Greedy Algorithms are algorithms that make locally optimal choices at each step in the hope of eventually reaching the globally optimal solution Problems must exhibit two properties in order to implement a Greedy solution: Optimal Substructure An optimal solution to the problem contains optimal ...
代码: class Solution { public: int dp[110][110],sum[110]; int stoneGameII(vector<int>& piles) { if(piles.size()==0)return 0; int n=piles.size(); for(int i=n-1;i>=0;i--)sum[i]=sum[i+1]+piles[i]; for(int i=0;i<n;i++){ ...
1classSolution {2privatevarsums = [Int](repeating:0, count:101)3privatevarhash = [[Int]](repeating: [Int](repeating:0, count:101), count:101)4func stoneGameII(_ piles: [Int]) ->Int {5let N =piles.count6ifN ==0{return0}7sums[N-1] = piles[N-1]8foriinstride(from: N-2,...