(int i : std::views::iota(1, Bound{10})) std::cout << i << ' '; std::cout << '\n'; for (int i : std::views::iota(1) | std::views::take(9)) std::cout << i << ' '; std::cout << '\n'; std::ranges::for_each(std::views::iota(1, 10), [](int i) ...
views::iota的迭代器operator*()的返回类型 * 不是 * 引用类型而是值类型，这使得它 * 不是 * 前...
当给定一个容器范围，我们通常需要对其中的每个元素执行相同的操作。这样的操作可能包括打印元素、修改元素...
std::vector<int>是一个连续的范围,但views::iota(0, 100)不是连续的,它只是随机访问。 旁注:写views::iota(0, 1000),不写ranges::iota_view{0, 1000}。几乎没有任何理由要重写ranges::meow_view,views::meow而且很容易变得更糟 - 后者并不总是给你属于前者类型的东西。将其视为meow_view实施细节。
3)Initializesvalue_withvalueandbound_withbound. This constructor is used to create bounded iota views, e.g.iota(10,20)yields numbers from 10 to 19. Parameters value-the starting value bound-the bound std::ranges::iota_view::begin constexpriterator begin(); ...
这里有两个版本的代码。一种在 std::for_each 调用中使用 std::vector 迭代器,另一种使用 std::views::iota 迭代器。我希望这两个都使用多线程,因为我...
operator-(iota_view::iterator,iota_view::sentinel) constexpr/*iterator*/begin()const; (since C++20) Returns aniteratorinitialized withvalue_. Parameters (none) Return value Aniterator Example Run this code #include <iostream>#include <ranges>intmain(){autoiota{std::views::iota(2,6)};autoite...
Usingstd::ranges::views::iotaused to initialise an explicit specialisation of a variable template causes an internal compiler error. For example: #include <ranges> template<typename T> auto foo = 1; template<> auto foo<int> = std::ranges::views::iota(1, 10); int main() {}...
Applyingstd::ranges::upper_boundover an iota view with along longvalue results in compilation failure when importing the standard library via thestdmodule instead of using the standard library headers: importstd;voidtest(){automax = std::ranges::upper_bound(std::views::iota(0LL,...
std::ranges::views::iota,std::ranges::iota_view Defined in header<ranges> template<std::weakly_incrementableW, std::semiregularBound=std::unreachable_sentinel_t> requires/*weakly-equality-comparable-with*/<W, Bound>&&std::copyable<W>