递归函数中的C++ std::future<bool> 计数std::vector<bool>中的设置值 使用std::future的不完整类型的使用无效 在内部是否使用std::condition_variable来通知相关的std::future? 选择临时表,重复值设置为NULL C++:添加将在std::future完成时执行的回调 为什么MinGW中仍然没有std::thread
~ThreadPool(); private: // 消费者线程 std::vector< std::thread > workers; //任务队列 std::queue< std::function<void()> > tasks; //互斥量 std::mutex queue_mutex; std::condition_variable condition; //停止信号,如果为true,则表示没有新的任务 bool stop; }; //构造函数,分配threads个消...
notify_one(); return res; } private: std::vector<std::thread> workers; std::queue<std::function<void()>> tasks; std::mutex queue_mutex; std::condition_variable condition; bool stop; }; int main() { ThreadPool pool(4); // 提交一个异步任务并获取 std::future...
将std::vector<std::unique_ptr<T>>移动到std::vector<std::shared_ptr<T>> std :: vector是否可以=另一个std :: vector? 如何使用boost::future重新抛出std::exception_ptr存储的原始异常? 为什么MinGW中仍然没有std::thread、std::promise和std::future?win32中的promise和futures的替代方案是什么?
get_future().share();//sf的类型是std::shared_future<void>std::vector<std::thread>vt;...
Unlike std::bitset, which was designed for bit manipulation, std::vector<bool> lacks bit manipulation member functions. Using std::vector<bool> For the most part, std::vector<bool> works just like a normal std::vector: #include <iostream> #include <vector> int main() { std::vector<boo...
get_future().share();//sf的类型是std::shared_future<void>std::vector<std::thread>vt;...
[](std::vector<double>& data) mutable{ /*使用data*/ }, std::move(data) ); 1. 2. 3. 4. 5. 如果要移动初始化的对象直接在std::bind中创建(如std::unique_ptr<Widget>),则可以这样做: auto func = std::bind( [](const std::unique_ptr<Widget>& pw){ ...
以下是使用std::thread,std::future,std::promise,std::async和std::packaged_task的自定义线程池实现。 #include <iostream>#include <vector>#include <queue>#include <thread>#include <mutex>#include <condition_variable>#include <functional>#include <future>class ThreadPool {public:// 构造函数: 创建...
The storage of the vector is handled automatically, being expanded as needed. Vectors usually occupy more space than static arrays, because more memory is allocated to handle future growth. This way a vector does not need to reallocate each time an element is inserted, but only when the additi...