#include <vector> #include <iostream> using std::vector; using std::cout; using std::cin; using std::endl; int main() { vector<unsigned> scores(11, 0); unsigned grade; while (cin >> grade) { if (grade <= 100) ++*(scores.begin() + grade / 10); } for (auto s : scores)...
(寻找被移除的元素)问题:原有长度为n+1公差为1等升数列,将数列输到程序的数组时移除了一个元素,导致长度为n的开序数组可能不再连续,除非被移除的是第一个或最后一个元素。需要在数组不连续时,找出被移除的元素。试补全程序。#include <iostream> #include <vector> usi
println!("{:?}", max(a.iter()).unwrap()); // Collect all the iterable's elements into a // sorted vector in ascending order. println!("{:?}", sorted(a.iter())); }lazy_static = "0.2.8" 📖Rust has strict rules about accessing global state. In particular there is no ...
线段树套vector: structBST{std::vector<int>V;inlinevoidins(intx){V.insert(std::lower_bound(V.begin(),V.end(),x),x);}inlinevoiddel(intx){V.erase(std::lower_bound(V.begin(),V.end(),x));}inlineintrnk(intx){returnstd::lower_bound(V.begin(),V.end(),x)-V.begin()+1;}inlin...
println!("{:?}", max(a.iter()).unwrap()); // Collect all the iterable's elements into a // sorted vector in ascending order. println!("{:?}", sorted(a.iter())); }lazy_static = "0.2.8" 📖Rust has strict rules about accessing global state. In particular there is no ...
println!("{:?}", max(a.iter()).unwrap()); // Collect all the iterable's elements into a // sorted vector in ascending order. println!("{:?}", sorted(a.iter())); }lazy_static = "0.2.8" 📖Rust has strict rules about accessing global state. In particular there is no ...