<cmath>#include <limits>intmain(){constlongdoublepi=std::acos(-1.L);std::cout<<"default precision (6): "<<pi<<'\n'<<"std::setprecision(10): "<<std::setprecision(10)<<pi<<'\n'<<"max precision: "<<std::setprecision(std::numeric_limits<longdouble>::digits10+1)<<pi<<'\n...
std::setprecision /*unspecified*/setprecision(intn); 用于表达式out<<setprecision(n)或in>>setprecision(n)时,设置流out或in的precision参数准确为n。 参数 n-精度的新值 返回值 返回未指定类型的对象,使得若str是std::basic_ostream<CharT, Traits>类型的输出流名称或std::basic_istream<CharT, Traits>类型...
{ const long double pi = std::acos(-1.L); std::cout << "default precision (6): " << pi << '\n' << "std::setprecision(10): " << std::setprecision(10) << pi << '\n' << "max precision: " << std::setprecision(std::numeric_limits<long double>::digits10 + 1) << ...
L); std::cout << "default precision (6): " << pi << '\n' << "std::setprecision(10): " << std::setprecision(10) << pi << '\n' << "max precision: " << std::setprecision(std::numeric_limits<long double>::digits10 + 1) << pi << '\n'; } 输出: default precision...
std::ofstream fout; fout.open("vector.txt"); for (l = 0; l < vector.size(); l++) fout << std::setprecision(10) << vector.at(l) << std::endl; fout.close(); 但这需要很长时间才能完成。有没有更快或更有效的方法来做到这一点?我很想看到并学习它。 原文由 Diego Fernando Pava...
#include <iostream> #include <iomanip> #include <cmath> #include <limits> int main() { const long double pi = std::acos(-1.L); std::cout << "default precision (6): " << pi << '\n' << "std::precision(10): " << std::setprecision(10) << pi << '\n' << "max ...
std::cout << std::setprecision(10) << value << std::endl; return 0; } 当运行上述代码时,你可能会得到与std::ios_base::floatfield相关的错误,具体错误信息取决于编译器和环境。 1.2 报错分析 这个错误表明在std::cout对象上设置了不正确的浮点数格式化标志。std::setprecision函数用于设置浮点数的输出...
<iomanip>#include <iostream>#include <list>#include <string>#include <vector>#include <numeric>#include <random>constintSIZE=100'000'000;template<typenameT>voidsumUp(T&t,conststd::string&cont){// (6)std::cout<<std::fixed<<std::setprecision(10);autobegin=std::chrono::steady_clock::now...
-pow:pow)/fac;returncos;}intmain(){std::cout<<std::setprecision(10)<<std::showpos<<"典型用法:\n"<<"std::cos(pi/3) = "<<std::cos(pi/3)<<'\n'<<"your cos(pi/3) = "<<your_cos(pi/3)<<'\n'<<"std::cos(pi/2) = "<<std::cos(pi/2)<<'\n'<<"your cos(pi/2)...
cout<<setprecision(10)<<f<<endl; // The value from the output f=-3.402823466e+38; // Read the binary representation // of the float as an integer x=*(int*)&f; cout<<bitset<8*sizeof(x)>(x) <<endl; return0; } 输出: