: true std::is_arithmetic<float*>::value ?: false std::is_arithmetic<std::complex<double>>::value ?: false std::is_arithmetic_v<char> ?: true std::is_arithmetic_v<float> ?: true std::is_arithmetic_v<float*> ?:
std::is_void std::is_null_pointer std::is_array std::is_pointer std::is_enum std::is_union std::is_class std::is_function std::is_object std::is_scalar std::is_compound std::is_floating_point std::is_fundamental std::is_arithmetic std::is_reference std::is_lvalue_reference std...
is_arithmetic_v<int&> == false and std::is_arithmetic_v<int*> == false and std::is_arithmetic_v<float&> == false and std::is_arithmetic_v<float*> == false and std::is_arithmetic_v<A> == false and std::is_arithmetic_v<B> == false and std::is_arithmetic_v<decltype(B::...
is_arithmetic_v<> (C++17 起)is_array<> (C++11 起)is_array_v<> (C++17 起)is_assignable<> (C++11 起)is_assignable_v<> (C++17 起)is_base_of<> (C++11 起)is_base_of_v<> (C++17 起)is_bind_expression<> (C++11 起)is_bind_expression_v<> (C++17 起)is_bounded_array<> (...
问C++ SFINAE - std::is_arithmetic和std::is_same之间的分辨率优先级EN在 C++ 编程中，有时候我们...
std::is_arithmetic 定义于头文件<type_traits> template<classT> structis_arithmetic; (C++11 起) 若T为算术类型(即整数类型或浮点类型)或其cv限定版本,则提供等于true的成员常量value。对于任何其他类型,value为false。 添加is_arithmetic或is_arithmetic_v(C++17 起)的特化的程序行为未定义。
; } emm,相信你也看出问题所在了,当然了,编译器也会提示如下错误: error: no viable conversion from 'const int' to 'std::string' (aka...::false_type {}; template struct is_stringstd::enabl...
is_integer identifies integer types (public static member constant of std::numeric_limits<T>) [static] is_floating_point checks if a type is a floating-point type (class template) (C++11) is_arithmetic checks if a type is an arithmetic type (class template) (C++11) is_enum che...
struct is_reference<_Tp&&> : public true_type { }; #endif /// is_arithmetic template<typename _Tp> @@ -3250,12 +3257,19 @@ template <typename _Tp> inline constexpr bool is_class_v = __is_class(_Tp); template <typename _Tp> inline constexpr bool is_function_v = is_function<...
If T is a fundamental type (that is, arithmetic type, void, or nullptr_t), provides the member constant value equal true. For any other type, value is false. If the program adds specializations for std::is_fundamental or std::is_fundamental_v, the behavior is undefined. Template para...