std::micro>usingstd::chrono::milliseconds=duration</*at least 45 bits int*/,std::milli>usingstd::chrono::seconds=duration</*at least 35 bits int*/>usingstd::chrono::minutes=duration</*at least 29 bits int*/,std::ratio<60>>
chrono::duration_cast< std::chrono::seconds >( duration ); duration -= seconds; auto milliseconds = std::chrono::duration_cast< std::chrono::milliseconds >( duration ); duration -= milliseconds; auto microseconds = std::chrono::duration_cast< std::chrono::microseconds >( duration ); ...
最后,我建议消除临时变量以将 time_point 和整数类型之间的代码转换减少到最低限度。这些转换是危险的,因此您编写的操作裸整数类型的代码越少越好:int main () { using namespace std::chrono; // Get current time with precision of milliseconds auto now = time_point_cast<milliseconds>(system_clock::now...
point指定duration，使用std::chrono::time_point<std::chrono::utc_clock, std::chrono::milliseconds...
std::chrono::milliseconds ms; std::chrono::microseconds cs; std::chrono::nanoseconds ns; switch (time_stamp_type) { case 0: ss << buffer; break; case 1: ms = std::chrono::duration_cast<std::chrono::milliseconds>(now.time_since_epoch()) % 1000; ...
31 // std::chrono::duration_cast 32 33 int main () 34 { 35 using namespace std::chrono; 36 // std::chrono::milliseconds is an instatiation of std::chrono::duration: 37 milliseconds foo (1000); // 1 second 38 foo*=60;
事实上，减去两个time_points并不产生time_point-它产生duration。在<chrono>中，durations和time_points...
{usingnamespacedate;usingnamespacestd::chrono;std::cout<< format("%D %T %Z\n",floor<milliseconds>(system_clock::now())); }09/15/1713:17:40.466UTC#include<chrono>#include<iomanip>#include<sstream>usingtime_point =std::chrono::system_clock::time_point;std::stringserializeTimePoint(constti...
chrono::duration_cast<std::chrono::seconds>(duration).count()<<" 秒"<<std::endl;std::cout<<"时间间隔为:"<<std::chrono::duration_cast<std::chrono::milliseconds>(duration).count()<<" 毫秒"<<std::endl;std::cout<<"时间间隔为:"<<std::chrono::duration_cast<std::chrono::microseconds...