{ using type = T; }; template <class T> struct unwrap_refwrapper<std::reference_wrapper<T>> { using type = T&; }; template <class T> using unwrap_decay_t = typename unwrap_refwrapper<typename std::decay<T>::type>::type; // 或使用 std::unwrap_ref_decay_t(C++20 起) template...
#include <iostream>#include <tuple>#include <functional>std::tuple<int,int>f()// 此函数返回多值{intx=5;returnstd::make_tuple(x,7);// return {x,7}; 于 C++17}intmain(){// 异类 tuple 构造intn=1;autot=std::make_tuple(10,"Test",3.14,std::ref(n), n);n=7;std::cout<<"The...
https://thispointer.com/c11-make_tuple-tutorial-example/ https://en.cppreference.com/w/cpp/utility/tuple/make_tuple
在没有tuple之前,如果函数需要返回多个值,则必须定义一个结构体,有了C++11,可以基于tuple直接做了,下面是个示例: // 编译:g++ -std=c++11 -g -o x x.cpp...include // tuple头文件 #include #include using namespace std...b) = foo(); printf("%d => %s\n", a, b.c_str()); // 注意...
(函数模板) forward_as_tuple 创建转发引用的tuple(函数模板) tuple_cat 通过连接任意数量的元组来创建一个tuple(函数模板) apply(C++17) 以一个实参的元组来调用函数(函数模板) unwrap_referenceunwrap_ref_decay(C++20)(C++20) 获取包装于 std::reference_wrapper 的引用类型(类模板)...
#include <iostream>#include <tuple>#include <functional>std::tuple<int,int>f()// 此函数返回多值{intx=5;returnstd::make_tuple(x,7);// return {x,7}; 于 C++17}intmain(){// 异类 tuple 构造intn=1;autot=std::make_tuple(10,"Test",3.14,std::ref(n), n);n=7;std::cout<<"The...
make_tuple std::make_tuple From cppreference.com Defined in header<tuple> template<class...Types> std::tuple<VTypes...>make_tuple(Types&&...args); (since C++11) (constexpr since C++14) Creates a tuple object, deducing the target type from the types of arguments....