int main() { int * p1 = static_cast < int* > ( std::malloc ( 10 * sizeof *p1 ) ); std::printf ( "default-aligned address: %p \n", static_cast < void* > ( p1) ); std::free ( p1 ); int * p2 = static_cast < int* > ( std::aligned_alloc ( 1024, 10 * sizeof ...
_cast<int*>(std::malloc(10*sizeof *p1)); std::printf("默认对齐地址: %p\n", static_cast<void*>(p1)); std::free(p1); int* p2 = static_cast<int*>(std::aligned_alloc(1024, 10*sizeof *p2)); std::printf("1024 字节对齐地址: %p\n", static_cast<void*>(p2)); std::free(...
(std::malloc(10*sizeof *p1)); std::printf("default-aligned address: %p\n", static_cast<void*>(p1)); std::free(p1); int* p2 = static_cast<int*>(std::aligned_alloc(1024, 10*sizeof *p2)); std::printf("1024-byte aligned address: %p\n", static_cast<void*>(p2)); std::...
对于类成员函数、lambda表达式或其他可调用对象就无能为力了，因此，C++11推出了std::function与std::...
马克-to-win @ 马克java社区：前面给出的例子，只是起到引入和说明的作用，所以只用了一些线性组合（...
{int*p1=static_cast<int*>(std::malloc(10*sizeof*p1));std::printf("default-aligned address: %p\n",static_cast<void*>(p1));std::free(p1);int*p2=static_cast<int*>(std::aligned_alloc(1024,1024));std::printf("1024-byte aligned address: %p\n",static_cast<void*>(p2));std::...