【情况一】:在静态方法中引用了一个非静态方法 报错:Non-static method 'xxx()' cannot be referenced from a static context 形如: 代码语言:javascript 代码运行次数:0 publicclassMyClass{publicvoidnonStaticMethod(){// 非静态方法实现}publicstatic
In above example, we have a non-static method named calculation. From the main method (static method), I'm trying to access that non-static method and to do this I need to create the instance of the class inside the main method (static method) because a static method only accesses the...
publicclassMain{publicstaticviodmain(String[] args){//Test01();//直接调用Test01会报Non-static method xx cannot be referenced from a static context.//用如下方式调用Test01Main m=newMain(); m.Test01();//Test02可以直接调用,通过类Main.Test02(); }publicviodTest01(){ System.out.println("此...
privatestaticString str1 ="staticProperty"; privateString str2 ="nonstaticProperty"; publicMyObject() { } publicvoidprint1() { System.out.println(str1);//非静态方法可以访问静态域 System.out.println(str2);//非静态方法可以访问非静态域 print2();//非静态方法可以访问静态方法 } publicstaticvoi...
当我们使用 Java 时,经常会遇到需要更深入地了解该语言的复杂性的问题。一个常见的难题是错误消息:“非静态方法……无法从静态上下文中引用。” 这个错误对于初学者来说可能令人望而生畏,甚至可能让经验丰富的程序员感到困惑。 在本教程中,我们将深入研究此错误背后的原因并探索解决方法。
In Java, methods can be static when belonging to a class, or non-static when an object of the class. Compare static and non-static methods through...
nonStaticMethod(); // 错误:Non-static method 'nonStaticMethod()' cannot be referenced from a static context } } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 解决这个问题的方法是,要么将非静态方法改为静态方法,或者在静态方法内部创建实例对象后调用非静态方法。
错误信息“Non-static method cannot be referenced from a static context”是因为Lambda表达式试图访问一个非静态的方法,而这个方法需要一个对象实例才能被调用。解决这个问题的方法有两种: 将方法声明为静态:如果可能的话,最简单的解决方案是将非静态方法声明为静态。这样,你就可以在Lambda表达式中直接调用它。
Use static methods only if the method dependsONLY ON ITS PARAMETERS. If you're reading from the config, making database calls or communicating with an outside resource in any way use an instance method. Seriously, the performance difference between a static and non-static method is so small ...
解决php报错：[8192]Non-static method 简介 php项目低版本升级高版本的时候，会遇到个错误：[8192]Non-static method app\api\controller\sss::xxx should not be called statically 工具/原料 php 方法/步骤 1 原因：php高版本的语法和低版本有差异造成的，php不做向后兼容，要不就使用低版本要不就修改代码。...