1、Quarterly date from daily date 导入数据,查看数据 use date.dtadesced 可以发现Date2 is a string date variable 然后进行转换 gen datevar=date(date2,"MDY", 2099)format datevar %tdgen quarterly = qofd(datevar)format quarterly %tq 2、Quarterly date from monthly ...
variable trunk was int now byte variable turn was int now byte variable make was str18 now str17 (370bytes saved) 2.Stata中的时间变量 clearall set obs10 gen date = _n format date %tdCY-N-D //年月日的数据格式 format 表示格式格式的调整。%td 表示时间 date, 除此之外,还有 月份、星期...
通过date函数进行转换,再通过format指定显示格式。 *第一步,用过date函数将字符串型的日期变量,转换为真正的日起变量 gen date1 = date(date, "YMD") *第二步,通过format命令,改变date1日期型变量的显示格式 format date1 %td 四、其它:季度和月度变量 季度变量,通过quarterly函数进行转换,再通过format指定显示...
1、Quarterly date from daily date 导入数据,查看数据 usedate.dtadesced 可以发现Date2 is a string date variable 然后进行转换 gen datevar=date(date2,"MDY", 2099)format datevar %tdgen quarterly = qofd(datevar)format quarterly %tq 2、Quarterly date from monthly date gen month = month(datevar...
time is a string variable 因此我们如果要在Stata中处理时间变量,第一件事就是要把文本格式的时间,转换成Stata可以识别的格式。转换的命令叫做date,其格式是: date(s1,s2),其中s1是文本格式的时间变量,s2是文本格式时间的年月日的排列次序 比如说,例子中的1987-01,就是YM,如果是1987-01-01,那就是YMD。如果...
name type format label Variable label --- patid byte %9.0g Patient ID dateofbirth str9 %9s Date of birth reason str15 %15s Reason for visit admit_d str8 %9s Admission date admit_t str17 %17s Admission date and time discharge_d str9 %9s Discharge...
name type format label Variable label --- patid byte %9.0g Patient ID dateofbirth str9 %9s Date of birth reason str15 %15s Reason for visit admit_d str8 %9s Admission date admit_t str17 %17s Admission date and time discharge_d str9 %9s Discharge...
尝试绘制图表时，Stata会报错提示“string variables not allowed in varlist; time is a string variable”。因此，处理时间变量的第一步是在Stata中将其从文本格式转换为可识别格式，使用`date`命令实现，格式为`date(s1, s2)`，其中`s1`为文本格式的时间变量，`s2`为年月日排列顺序，如`YM`表示...
Stata日期和时间处理指南说明书 in Stata Gabriela Ortiz Applied Econometrician StataCorp LLC 1
To convert the above date variable to an elapsed date format, you must first convert the numeric variable to a string and then use thedate()function. For example, . tostring datevar, replace format(%20.0f)datevar was long now str8. replace datevar = "0" + datevar if length(datevar)...