Stack<int> stack = new Stack<int>(); // 压栈 stack.Push(10); stack.Push(20); stack.Push(30); // 查看堆栈顶部 Console.WriteLine($"Peek: {stack.Peek()}"); // 输出:30 // 弹栈 Console.WriteLine($"Pop: {stack.Pop()}"); // 输出:30 // 剩余堆栈 Console.WriteLine("Remaining ...
#include"Stack.h"template<classT>classseqStack:publicStack<T>{private:T*data;int top;int maxSize;voidresize();public:seqStack(int initSize=100){if(initSize<=0)throwbadSize();data=newT[initSize];maxSize=initSize;top=-1;}~seqStack(){delete[]data;}boolempty()const{returntop==-1;}intsi...
class Student{ int age; String name; public Student(int Age, String Name) { this.age = Age; setName(Name); } public void setName(String Name) { this.name = Name; } } public class Main{ public static void main(String[] args) { Student s; s = new Student(23,"Jonh"); } } ...
出栈操作:int value=stack[top]; top--;return value; 源代码 packagecom.atxihua;importjava.util.Scanner;publicclassArrayStackDemo {publicstaticvoidmain(String[] args) {//测试//先创建一个ArrayStack对象表示栈ArrayStack stack=newArrayStack(4); String key="";booleanloop=true;//控制是否退出菜单Scanner ...
一、stack的三种解释stack有三种解释,我个人理解如下。1、用户自定义的stack用户自定义的stack就是一般意义上的后进先出队列,从名字上就能理解了,stack由下向上增长,有一个顶指针,一般来说有push,pop,top和isempty方法,具体的后面代码会展示。2、程序的call st
Stack<Integer> stack = new Stack<Integer>(); System.out.println("新建栈stack是否为空 : "+(stack.empty() ? "空" : stack.size())); //push : 把项压入堆栈顶部,返回值泛型指定的类型 //此处将1到5压入栈中 stack.push(1); stack.push(2); ...
public voidMethod1(){int i=4;int y=2;class1 cls1=newclass1();} 上面代码的Method1方法,共包含了三个变量:i, y 和 cls1。其中,i和y的值是整数,内存占用空间是确定的,而且是局部变量,只用在Method1区块之内,不会用于区块之外。cls1也是局部变量,但是类型为指针变量,指向一个对象的实例。指针变量占用...
inttop;//栈顶的位置 intcapacity;//容量 }ST; //栈的初始化 voidStackInit(ST*ps); //栈的销毁 voidStackDesroy(ST*ps); // push就是放栈顶 voidStackPush(ST*ps,STDataTypex); voidStackPop(ST*ps);//删除 STDataTypeStackTop(ST*ps);//查看栈顶的数据 ...
public void test(int x) { Stack<Integer> s1 = new Stack<Integer>(); Stack<Integer> s2 = new Stack<Integer>(); s1.push(x); s2.push(x); int p1 = s1.peek(); int p2 = s2.peek(); System.out.println(p1==p2); System.out.println(s1.peek() == s2.peek()); } 如果x在[...
#include <iostream> #include <stack> using namespace std; int main(void) { stack<int> stack1; cout << "push 1 2 3 to stack" << endl; stack1.push(1); stack1.push(2); stack1.push(3); cout << "now pop all elements in stack: "; while (!stack1.empty()) { cout << stac...