设计一个支持 push ,pop ,top 操作,并能在常数时间内检索到最小元素的栈。 push(x) —— 将元素 x 推入栈中。 pop() —— 删除栈顶的元素。 top() —— 获取栈顶元素。 getMin() —— 检索栈中的最小元素。 解题思路:设计两个栈,其中一个栈负责添加元素,另外一个栈的栈顶存放当前最小的元素即可。
publicbooleanisValid(Strings) {if(s.contains("()") || s.contains("[]") || s.contains("{}")) {returnisValid(s.replace("()","").replace("[]","").replace("{}",""));}else{return"".equals(s);}} 2. 最小栈(leetcode-155)# 设计一个支持 push ,pop ,top操作,并能在【常数...
1. leetcode_easy_stack_1441. Build an Array With Stack Operations; 完
1047. Remove All Adjacent Duplicates In String solution#1: 使用stack; code: solution#2: 快慢指针; code solution#3: 数据类型string的特性; code 参考 1. leetcode_easy_stack_1047. Remove All Adjacent Duplicates In String; 完...
pandas/easy pandas/easy/method_chaining.py Nov 1, 2023 shell shell/medium/word_frequency.sh Nov 13, 2021 .clang-format algorithms/easy/average_value_of_even_numbers_that_are_divisible_by_t… Oct 31, 2022 .gitignore ignore Dec 30, 2018 LICENSE Create LICENSE Dec 15, 2021 README.md update...
For regular desktop internet users, you can get also this Leetcode Night Mode version on your favorite web browser. That is with the Night Mode option in the Turn Off the Lights Browser extension. Follow the steps below on how to enable this free solution in your web b...
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(Notes: "馃摉" means you need to subscribe to [LeetCode premium membership](https://leetcode.com/subscribe/) for the access to premium questions.) ## Algorithms * [Bit Manipulation](https://github.com/kamyu104/LeetCode#bit-manipulation) * [Array](https://github.com/kamyu104/LeetCode#...
LeetCode 第20题--括号匹配 1. 题目 2.题目分析与思路 3.代码 1. 题目 给定一个只包括 '(',')','{','}','[',']' 的字符串,判断字符串是否有效. 有效字符串需满足: 左括号必须用相同类型的右括号闭合.左括号必须以正确的顺序闭合.注意空字符串可被认为是有效字符串. 2. 思路 这道题是简单题,...