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@Controller public class UserController { @Autowired private UserService userService; @RequestMapping(“/findByName”) public String findByName( @RequestParam(defaultValue=”1″) Integer currentPage, HttpServletRequest request,Map<String,Object> map) { String username=request.getParameter(“search”); ...
functionpageList(pageNo,pageSize){//第几页,展现几条//将隐藏域中的内容放到search框里面$("#search-name").val($.trim($("#hidden-name").val()));$("#search-owner").val($.trim($("#hidden-owner").val()));$("#hsearch-startDate").val($.trim($("#hidden-startDate").val()));$...
// dep下的search请求会由search方法处理 @RequestMapping("search") public ModelAndView search() { ModelAndView mv = new ModelAndView("dep/show"); List<Department> list = depService.search(); mv.addObject("list", list); return mv; } @RequestMapping("showAdd") public String showAdd() { retur...
摁,就这风格了,而且我还发现右上角的【Search】框是下载的模板用 js 实现的...对于管理来说更加方便了...而且居然还实现了分页... 一个邪恶的想法又诞生了... 一些规定 为了降低项目的难度,我们做了很多的精简,现在我们作出如下的规定: 全站没有商家,只有一家 Tmall ,后台没有验证,可以直接进入 前台...
So, with the use of SSM’s company name search function, you are able to detect if the name you created is unique or not. Smartly use the search function to check if your desired name is taken or not. And if it’s taken, you have no choice but to choose another unique name. ...
List<Member> getMemberListByKey(@Param("search_option")String searchOption,@Param("search_key")String searchKey); MySQL: 最开始使用#{ },出现 Parameter index out of range (2 > number of parameters, which is 1) 错误, 原因是因为,#{ } 带单引号,${ } 不带单引号,将#换成$即可解决 ...
public String order_search( HttpServletRequest request) { return "/admin/order_search"; } @RequestMapping("ordergetallbydelivery") public String ordergetallbydelivery(HttpServletRequest request){ String delivery=request.getParameter("delivery"); ...
二、CSS样式 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 .header_search{ float:left; padding:16px000px; } .header_search .search{ width:270px; height...
1. public static int commonBi narySearch(int[] arr, int key) { 2. 3. int low = 0; 4. 5. int high = arr.length 一 1; 6. 7. int middle = 0; 8. 9. if(key < arr[low] 十 key > arr[high] || 1ow > high) { 10. 11. return - 1; 12. 13. } 14. 15. while(1...