Yes, the square root of 72 can be simplified and can be expressed in radical form as 6√2. What is the square root of 72 rounded to its nearest tenth? Rounding off the square root of 72 to its nearest tenth means to have one digit after the decimal point. ...
3 square root of 125 simplified Can the square root of 10 be simplified? Simplify the following radical expression: 4 sqrt (625) Simplify the following radical expression : 4 \sqrt {\frac{(81)}{(16) a) \frac{2}{3}\b) \frac{3}{2}\c) 2\d) 3 ...
Why can't the square root of a^2 + b^2 be simplified? Why do negative numbers in parentheses squared become positive? Why is root 24=2 cubed root 3? Why does the square root of x^2+a^2 equals x+a? Why does a negative come out from the difference of squares?
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Functions are a special type of relations wherein it could be one to one (one domain value to one range value) or many to one (many domains to one range value) relation.Answer and Explanation: The square root of all the real numbers is not a function because of its one to ...
Is the square root of 288 infinite? The decimal expansion of√288 is infinite because it is non-terminating and non-repeating. The square root of 16 is 4, which is a rational number. What is the square root of 288 in simplified form?
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First, let's ask ourselves which square roots can be simplified. To answer it, you need to take the number which is after the square root symbol and find its factors. If any of its factors are square numbers (4, 9, 16, 25, 36, 49, 64 and so on), then you can simplify the sq...
3 square root of 125 simplified Can the square root of 10 be simplified? How do you simplify the square root of 6 times square root of 60? Simplify (x - square root 2)(2x + square root 8) Show all steps. Calculate dy / dx. Simplify your answer. y = x^9 square root x. ...
(if i=radical -1) \sqrt {\frac{13}{49 =? Why can't the square root of a^2 + b^2 be simplified? Prove that square root of 5 is irrational. Explain why the square root of 395.14 is 19.9. If { \sqrt{1-x^2} + \sqrt{ 1-y^2} = a(x+y) } then prove { \frac{...