What is the fastest complexity and how to achieve it? Is it just brute force or is there an efficient algorithm to solve this? Edit: I just realised that this can be solved in aroundO(N2M)O(N2M)using simple DP. But can it be solved faster than that? Edit 2: Turns out, some val...
Vasya claims that he had a paper square. He cut it into two rectangular parts using one vertical or horizontal cut. Then Vasya informed you the dimensions of these two rectangular parts. You need to check whether Vasya originally had a square. In other words, check if it is possible to m...
CodeForces Algorithms. Contribute to m-aprameya/CodeForces development by creating an account on GitHub.
Non-Working Days Simple REST API for checking working, non-working or short days for Russia, CIS, USA and other No Yes Yes Russian Calendar Check if a date is a Russian holiday or not No Yes No UK Bank Holidays Bank holidays in England and Wales, Scotland and Northern Ireland No Yes ...
I've come across the following task from z-trening (http://www.z-trening.com/tasks.php?show_task=5000000148). First I thought it would be easy with backtracking since sides where small. But I'm getting TLE in two cases, and when trying to solve a 5x5 square with all its squares em...
And here is a program to check whether the number is prime or not in C++: int isprime(int x) { int flag = 1; for (int i = 2; i <= (x/2); i++) if (x%i==0) { flag = 0; break; } return flag; } Now let’s talk about the Square Root of x. ...
Codeforces (Percentile) 17.5 35.6 24.8 25.3 20.3 23.6 51.6 SWE Verified (Resolved) - 22.6 23.8 24.5 50.8 38.8 42.0 Aider-Edit (Acc.) 60.3 71.6 65.4 63.9 84.2 72.9 79.7 Aider-Polyglot (Acc.) - 18.2 7.6 5.8 45.3 16.0 49.6 Math AIME 2024 (Pass@1) 4.6 16.7 23.3 23.3 16.0 9.3 39.2 MATH...
Non-Working Days Simple REST API for checking working, non-working or short days for Russia, CIS, USA and other No Yes Yes Russian Calendar Check if a date is a Russian holiday or not No Yes No UK Bank Holidays Bank holidays in England and Wales, Scotland and Northern Ireland No Yes ...
If both are 11 or both are −1−1, the result would be 11 or −1−1 modulo x2−yx2−y as well. However if z+az+a is a quadratic residue while z−az−a is not (hence one makes 11, the other makes −1−1), then {a0+a1x≡1(modx−a),a0+a1x≡−1(mo...
Solution : The given square matrix can be visualised as a NxN chessboard with cells of black and white colour. So we can say that if one pair of cell with opposite colours is removed then only the solution is possible. (As domino tiling matches one black cell with one white cell or vi...