I thought something like this might work, but I don't think the SUM expression is being evaluated correctly in the case statement as it returns only the "else" condition. select t.range as [price range], COUNT(*) as [orders] from ( select case when SUM(o.subtotal - o.discount - o...
1 Using SELECT CASE and SUM: MYSQL 26 MySQL using Sum and Case 0 MYSQL case statement with sum query 0 MySQL CASE with SUM function 1 SUM with CASE Statement in mysql 1 Mysql SUM inside a CASE 0 MySQL SUM over CASE statement 0 MySQL Sum and case 3 CASE Statement with a...
Case Statement returning multiple values CASE statement returns "Invalid Column Name" Error Case statement that increments variable with 1 is giving error Case Statement using Divide CASE Statement when not null , else if Help Case statement with Between in Where Clause Case statement with Date Compa...
3. 求 1、2 的交集。这有点麻烦,SQL 不支持步骤化,上两步的计算结果无法保存,只能再重抄一遍了...
1.CASE 写法如下: CASEWHENcondition1THENresult1WHENcondition2THENresult2WHENconditionNTHENresultNELSEresultEND; 解释:1)先匹配第一条,不匹配的话继续第二条,如此循环,只要找到匹配的就终止。如果都没有匹配的,就返回 ELSE里的语句, 2)如果都没匹配,而且没有ELSE语句就返回NULL值。
Oracle SQL练习之Sum,Count,Decode,Case…When的使用 技术标签:OracleDecodeSumCountCase 最近在做报表,写了一些SQL,整理一下,其中涉及到Oracle很多语法的使用,方便大家参考与复习! SELECT RESULT.SITE_ID,RESULT.SITE_NAME,RESULT.STATION_TYPE,RESULT.STATION_NAME,RESULT.MONITOR_TIME,RESULT.PROJECT_ID,RESULT.P.....
This way you can find out the total sum or sum of unique values stored in a numeric column. Use case with GROUP BY, HAVING, and ORDER BY statement Suppose you got a requirement to return a total number of units sold along with their total values, then we can use the SQL SUM functi...
Let’s illustrate with an example. The following SQL statement will return "Monday" if today is a Monday, otherwise it returns "Not a Monday". SETDATEFIRST1;-- first day of the week is a MondaySELECTCASEWHENDATEPART(WEEKDAY,GETDATE())=1THEN'Monday'ELSE'Not a Monday'END; ...
SUM(CASE WHEN Result='胜'THEN 1 ELSE 0 END) AS'胜', SUM(CASE WHEN Result='负'THEN 1 ELSE 0 END) AS'负'FROM Test GROUP BY Date; 3,行列转换 product_type sum_price clothes5000office600kitchen10000 sum_price_clothes sum_price_office sum_price_kitchen5000 600 10000 ...
[LOCATION],sum(casewhen[PAID_HOURS]>30then1else0end)as[COUNT_OVER_30],sum(casewhen[PAID_HOURS]<20then1else0end)as[COUNT_UNDER_20]frommydb.payrollgroupby[WEEKENDING],[LOCATION] This is the source table: Here is the desired result: ...