SquareRoot(Nullable<Decimal>) 傳回指定數字的平方根。 C# 複製 [System.Data.Objects.DataClasses.EdmFunction("SqlServer", "SQRT")] public static double? SquareRoot(decimal? arg); 參數 arg Nullable<Decimal> 一個數值運算式。 傳回 Nullable<Double> 輸入值的平方根。 屬性 EdmFunctionAttribute ...
Returns the square root of the specified number. C# Copy [System.Data.Objects.DataClasses.EdmFunction("SqlServer", "SQRT")] public static double? SquareRoot(decimal? arg); Parameters arg Nullable<Decimal> A numeric expression. Returns Nullable<Double> The square root of the input value. ...
SELECTsqrt(25)ASsquare_root; 以上查询将返回5,因为5的平方根是5。 如何在SQL中实现开方函数 如果你需要在SQL中实现开方函数,但你的数据库管理系统没有内置的开方函数怎么办?下面是一种在SQL中自定义开方函数的方法。 1.创建一个新的函数 •首先,你需要使用CREATE FUNCTION语句创建一个新的函数。函数需要一个...
例子:let tmp_float = pow(2,3) --8.00000000 4)ROOT(COLNAME/EXPRESSION,[INDEX]) 返回指定列或表达式的根值 5)SQRT(COLNAME/EXPRESSION) 返回指定列或表达式的平方根值 6)ROUND(COLNAME/EXPRESSION,[FACTOR]) 返回指定列或表达式的圆整化值 7)TRUNC(COLNAME/EXPRESSION,[FACTOR]) 返回指定列或表达式的截尾...
Window function: STDDEV( <expression> ) <window_specification> Returns the standard deviation of the given expression as the square root of the VAR function. STDDEV_POP(<expression>) Returns the standard deviation of the given expression as the square root of the VAR_POP function. ...
SQRTReturns the square root of a number SQUAREReturns the square of a number SUMCalculates the sum of a set of values TANReturns the tangent of a number SQL Server Date Functions SQL Server Advanced Functions FunctionDescription CASTConverts a value (of any type) into a specified datatype ...
The square root of 9 is 3, because 3 * 3 = 9. It doesn’t always have to be a whole number, as you’ll see in the examples section below. This function exists in Oracle, SQL Server, MySQL, and Postgres. In MySQL, the POWER function is the same as the POW function. ...
Function).Sort() The square root of 0 = 0 The square root of 1 = 1 The square root of 2 = 1.414213562373095049 The square root of 3 = 1.732050807568877294 The square root of 4 = 2 The square root of 5 = 2.236067977499789697 The square root of 6 = 2.449489742783178098 The square root ...
square root of the specified float value.','abs': 'Computes the absolutle value.','max': 'Aggregate function: returns the maximum value of the expression in a group.','min': 'Aggregate function: returns the minimum value of the expression in a group.','first': 'Aggregate function: ...
/// d ##class(PHA.TEST.SQLFunction).Sort() ClassMethod Sort() { s a = 0 while a < 11 { &sql( SELECT SQRT(:a) INTO :b ) if SQLCODE '= 0 { w !,"Error code ",SQLCODE } else { w !,"The square root of ",a," = ",b s a = a + 1 } } } 代码语言:javascript 代码...