Applies to: SQL Server Azure SQL Managed InstancePartitioning makes large tables or indexes more manageable because partitioning enables you to manage and access subsets of data quickly and efficiently, and mai
SQL Server Replication Sql Server Replication Scripting Setup 1. 大概的一个拓扑, 我们将三种角色分别安装在三台不同的 sql server 服务器上 1.1 distributor 1.2 publisher, publication, article 1.3 subscr…
SET Value=REPLICATE('X',2000) WHERE RowID%5=1 --查看索引占用的页数 SELECT ,ps.in_row_data_page_count FROM sys.indexes i INNER JOIN sys.dm_db_partition_stats ps ON i.object_id=ps.object_id AND i.index_id=ps.index_id WHERE ='CLUS_IndexIO' --重建索引 ALTER INDEX CLUS_IndexIO ON...
这个语句在SQL Server 7.0出错而不会被执行,SQL Server 2000中会执行,但会收到一个警告,超过8060的行可能会被截断。而在SQL Server 2005/2008中,你不但可以创建表,而且可以插入超过8060字节的数据。如下: INSERTINTOdbo.bigrows SELECTREPLICATE('e',2100),REPLICATE('f',2100), REPLICATE('g',2100),REPLICATE...
SET Value=REPLICATE('X',2000) WHERE RowID%5=1 --查看索引占用的页数 SELECT i.name,ps.in_row_data_page_count FROM sys.indexes i INNER JOIN sys.dm_db_partition_stats ps ON i.object_id=ps.object_id AND i.index_id=ps.index_id ...
Snapshot replication is most appropriate when data changes are substantial but infrequent. For example, if a sales organization maintains a product price list and the prices are all updated at the same time once or twice each year, you should replicate the entire snapshot of data after it chan...
SQL Server版本:2012 首先通过日志文件查看器,简单获取JOB的运行情况,可以发现如下几个问题: 1、该JOB共131个step,其实就是131个存储过程 2、历史日志中,总运行时间从1天到2天不等 3、1月30日运行了12个小时还未跑完,我开始介入进行调优 可以通过如下的SQL语句,查询出JOB中哪个步骤最耗费时间: ...
VALUES (@i, REPLICATE('a', 5000)) SET @i += 1 END GO 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 但你在表上执行sp_help的系统存储过程,你可以看到在主文件组里看到2个索引(聚集索引和非聚集苏音)。
Replicate Data in Encrypted Columns (SQL Server Management Studio)Article 09/28/2024 7 contributors Feedback In this article Examples Related content Applies to: SQL Server Azure SQL Managed Instance Replication enables you to publish encrypted column data. To decrypt ...
USE Testdb; go DROP TABLE bigrows; go CREATE TABLE bigrows ( a int IDENTITY , b varchar(1600), c varchar(1600) ); go INSERT INTO bigrows VALUES (REPLICATE('a', 1600), ''); INSERT INTO bigrows VALUES (REPLICATE('b', 1600), ''); INSERT INTO bigrows VALUES (REPLICATE('c', ...