假设两个表中一个较小,一个是大表,则子查询表大的用exists,子查询表小的用in: 比如:表A(小表),表B(大表) select * from A where cc in (select cc from B)效率低,用到了A表上cc列的索引; select * from A where exists(select cc from B where cc=A.cc)效率高,用到了B表上cc列的索引。
SELECT * FROM Employees where FirstName IN (SELECT * FROM STRING_SPLIT(@FirstNamesList, ',')) Using STRING_SPLIT in a JOIN operation Declare @FirstNamesList nvarchar(100) = 'Mark,John,Sara' SELECT Employees.* FROM Employees JOIN STRING_SPLIT(@FirstNamesList, ',') Result ON Result.VALU...
where stId in(select distinct stId from score where score >all(select score from score where stId=(select stId from Student where stName= 'Kaka') )); 3). 多行子查询使用ANY操作符号例子:查询有一门以上的成绩高于Kaka的任何一门成绩的学生的名字: sql> select stName from Student where stId...
下面是一个使用PreparedStatement实现IN查询的示例代码: Stringsql="SELECT column_name FROM table_name WHERE column_name IN (?, ?, ?)";List<String>values=Arrays.asList("value1","value2","value3");try(Connectionconn=DriverManager.getConnection(url,username,password);PreparedStatementstmt=conn.prepareS...
1--in/not in(list)23--查询部分号是10和20的员工45selecte.*67fromemp e89wheree.deptnoin(10,20);10111213selecte.*1415fromemp e1617wheree.deptnonotin(10,20);18192021--查询薪资是1000,2000,5000的员工2223selecte.*2425fromemp e2627wheree.salin(1000,2000,5000); ...
sql select in语句 SQL SELECT IN语句用于在一组给定的值中进行搜索。它可以在WHERE子句中使用,以选择符合给定值列表中任何一个条件的行。 语法如下: ``` SELECT column_name(s) FROM table_name WHERE column_name IN (value1, value2, ...); ``` 其中,column_name是要检索的列的名称,table_name是要...
IN操作符用于在WHERE子句中指定多个可能的值。其基本语法如下: SELECT column1, column2, ... FROM table_name WHERE column_name IN (value1, value2, ...); column1, column2, ...:要选择的列名。 table_name:要查询的表名。 column_name:要匹配的列名。
Column ‘student.score' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause. 出现以上错误的原因是因为一个学生id对应多个分数,如果我们简单的在SELECT语句中写上score,则无法判断应该输出哪一个分数。如果想用score作为select语句的参数可以将它用...
var list = query_list(cn, sql, values, [VARCHAR,VARCHAR]); // 或者参考如下 var types = []; var sql = "selectfidfrom" + table + "wherefnumbernotin("; for(var index = 0; index < v_exclude_number.length; index++) { if(index == v_exclude_number.length - 1) { ...
1055(42000): SELECT list is not in GROUP BY clause and contains nonaggregated column 原因与解决方案 该报错主要是因为sql_mode参数被修改导致: 原因一:用户修改sql_mode参数导致GROUP BY的语法不合规 原因:用户修改了sql_mode参数,添加了ONLY_FULL_GROUP_BY条件,导致GROUP BY的语法不符...