This function adds anumber(a signed integer) to adatepartof an inputdate, and returns a modified date/time value. For example, you can use this function to find the date that is 7,000 minutes from today:number= 7000,datepart= minute,date= today. ...
实现带分钟的日期时间和整数相互转换的功能函数,T-SQL代码如下: 1IF OBJECT_ID(N'dbo.ufn_Minutes','FN') IS NOT NULL2BEGIN3DROP FUNCTION dbo.ufn_Minutes;4END5GO67--===8--功能: 获得指定的日期时间基于基准日期的总小时数(一个整数值)9-- 说明: 如果指定的日期时间为NULL或者小于基准日期“1900-0...
RETURN DATEADD(DAY, @intDays, dbo.ufn_GetDefaultBasedate()); END GO IF OBJECT_ID(N'dbo.ufn_DayOfWeek', 'FN') IS NOT NULL BEGIN DROP FUNCTION dbo.ufn_DayOfWeek; END GO --=== -- 功能: 获取指定日期时间的所在当前周的日索引 -- 说明: 运行在SQL Server 2005+。 -- 结果值从1到7,分...
ADDTIME() MySQL Function is used to add an interval of hours, minutes, seconds, or milliseconds to the Time.TIMEDIFF()Function is used to subtract an interval to the time
2. dateadd 在向指定日期加上一段时间的基础上,返回新的 datetime 值 例如:向日期加上2天 select dateadd(day,2,'2004-10-15') --返回:2004-10-17 00:00:00.000 3. datediff 返回跨两个指定日期的日期和时间边界数。 select datediff(day,'2004-09-01','2004-09-18') --返回:17 ...
(total_rows AS float)*100 AS [% fragmented], created_time FROM sys.dm_db_column_store_row_group_physical_stats WHERE object_id = OBJECT_ID('FactOnlineSales2') AND state_desc = 'COMPRESSED' AND deleted_rows > 0 AND created_time > DATEADD(day...
SELECT DATEADD(month, -(10 / 2), SYSDATETIME()); Specify ranking functions as number This example uses a ranking function as an argument for number. SQL Copy SELECT p.FirstName, p.LastName, DATEADD(day, ROW_NUMBER() OVER (ORDER BY a.PostalCode), SYSDATETIME()) AS 'Row Number' ...
dateTimeOffset.AddMinutes(minutes)DATEADD(minute, @minutes, @dateTimeOffset) dateTimeOffset.AddMonths(months)DATEADD(month, @months, @dateTimeOffset) dateTimeOffset.AddSeconds(seconds)DATEADD(second, @seconds, @dateTimeOffset) dateTimeOffset.AddYears(years)DATEADD(year, @years, @dateTimeOffset) ...
29 DROP FUNCTION dbo.ufn_MinutesOfDay; 30 END 31 GO 32 33 --=== 34 -- 功能: 获取指定的日期时间基于所在当前日午夜零时的分钟数 35 -- 作者: 结果值从0开始计数,包括0、1、2、3、1439 36 -- 作者: XXX 37 -- 创建: yyyy-MM-dd ...
IF DATEADD(dd, -@days, @date2) < @date1SELECT@days= @days-1;SET@date2 =DATEADD(dd, -@days, @date2);SELECT@hours=DATEDIFF(hh, @date1, @date2); IF DATEADD(hh, -@hours, @date2) < @date1SELECT@hours= @hours-1;SET@date2 =DATEADD(hh, -@hours, @date2);SELECT@minutes=DATED...