AI代码解释 importjava.io.*;publicclassMain{publicstaticvoidmain(String[]args)throws IOException{BufferedReader reader=newBufferedReader(newInputStreamReader(System.in));String[]strs=reader.readLine().split(" ");int res=0;for(int i=0;i<strs.length;++i){res+=Integer.parseInt(strs[i]);}Sys...
因为在s1中没有遇到和s2不匹配的 如果连1.遇到匹配s2的都不满足，则会返回整个字符串。测试代码：Stri...
1. String s2="this is a test"; 2. String sarray[]=s2.split("/s"); 3. System.out.println("sarray.length="+sarray.length); 1. 2. 3. AI检测代码解析 String s2="this is a test";String sarray[]=s2.split("/s");System.out.println("sarray.length="+sarray.length); 1. 这个...
还是上述例子,如果对字符串"a.|b.c"按照".|"进行拆分,使用StringUtils.split可以吗? // 问题:请使用“.|”拆分Stringstr="a.|b.c";String[]s2=StringUtils.split(str,".|");/* 运行结果:[a, b, c] 并不是期望的[a, b.c] */ 答案是不行,拆分的结果是[a, b, c],并不是期望的[a, b.c...
[] s2 = str2.split("\\."); for(int j=0;j<s2.length;j++){ System.out.print(s2[j]+" "); } System.out.println("\n---"); String str3 = "aaa|bbb|ccc|ddd"; //String[] s3 = str3.split("|"); //得到错误的结果 String[] s3 = str3.split("\\|"); for(int k=0;...
String[] splitAddress=address.split("\\^|@|#");//举例:Scanners =newScanner(System.in);Strings2 = s.nextLine();String[] s3 = s2.split("\\^|@|#");//如果使用多个分隔符则需要借助 | 符号for(Stringt:s3){System.out.println(t); ...
String常用方法 1. public class StringMethodTest { @Test public void test2() { String s1 =“Hello world”; String s2 =“hello world”; System.out.println(s1.equals(s2)); System.out.prin...Java中String类的常用方法源码解析(二) Hello,大家好,我是Steafan,这周的工作有点忙,没来得急更新博...
String本质上是final String s1 = “a”; 此时s1指的是常量池中的"a" String s2= s1 + “b”; 此时s2指的是堆里面的"ab",原来的"a"字符串对象已经丢失,在堆空间里面产生一个字符串s1+“b”。这样是会降低效率,尤其是... String的indexOf(),lastIndexOf(),substring(int x),substring(int x , in...
The strings S1, S2 and S3 should have characters in the same order as they appear in input. Example Following is the code − const str = "Th!s String C0nt@1ns d1fferent ch@ract5rs"; const seperateCharacters = str => { const strArr = str.split(""); return strArr.reduce((acc...
s2 = arg2.toString(); try { m += s1.split(".")[1].length } catch (e) { } try { m += s2.split(".")[1].length } catch (e) { } return Number(s1.replace(".", "")) * Number(s2.replace(".", "")) / Math.pow(10, m) ...