Solution: Given an m X n matrix, traverse it in a clockwise spiral order. My solution is to simulate the traversal. Two variables are required, the "position" and the "direction". Starting from the grid (0, 0), going right, the traversal keeps moving forward in one direction, until it...
Still spiral order traversal of an m X n matrix, please see "LeetCode - Spiral Matrix" for more detail. Time complexity is O(m * n), space complexity is O(1). Accepted code: 1//4CE, 2RE, 1AC, such a terrible record..2classSolution {3public:4vector<vector<int> > generateMatrix...
package leetcode func generateMatrix(n int) [][]int { if n == 0 { return [][]int{} } if n == 1 { return [][]int{[]int{1}} } res, visit, round, x, y, spDir := make([][]int, n), make([][]int, n), 0, 0, 0, [][]int{ []int{0, 1}, // 朝右 []int...
https://leetcode.com/problems/spiral-matrix/discuss/20571/1-liner-in-Python-%2B-Ruby Solutions 代码语言:javascript 代码运行次数:0 运行 AI代码解释 1publicList<Integer>spiralOrder(int[][]matrix){2List<Integer>res=newArrayList<>();34if(matrix==null||matrix.length==0||matrix[0].length==0){...
0542-01-Matrix 0557-Reverse-Words-in-a-String-III 0559-Maximum-Depth-of-N-ary-Tree 0561-Array-Partition-I 0563-Binary-Tree-Tilt 0572-Subtree-of-Another-Tree 0583-Delete-Operation-for-Two-Strings 0589-N-ary-Tree-Preorder-Traversal 0590-N-ary-Tree-Postorder-Transversal...
Leetcode Spiral Matrix Given a matrix ofmxnelements (mrows,ncolumns), return all elements of the matrix in spiral order. For example, Given the following matrix: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ] You should return[1,2,3,6,9,8,7,4,5]....
vector<int> spiralOrder(vector<vector<int>>&matrix) { vector<int>ret;constintm =matrix.size();if(m<1)returnret;constintn = matrix[0].size();constintcircle = std::min(n, m)/2;for(intc=0; c<circle; ++c ) {//traversal a circle//up rowfor(intcol=c; col<n-c; ++col ) re...
vector<int> spiralOrder(vector<vector<int>>&matrix) { vector<int>res;intheight=matrix.size();if( height==0)returnres;intwidth=matrix[0].size(); vector<vector<int>> flag(height,vector<int>(width,1));//用来记录是否走过intm=0;intn=0; ...