matrix[i][left]=num num+=1 left+=1 returnmatrix if __name__=="__main__": n=3 test=Solution() print(test.spiralMatrixII(n)) golang packagemain import"fmt" funcmain(){ n :=3 fmt.Println(spiralMatrixII(n)) } // 模拟行为,螺旋矩阵II funcspiralMatrixII(nint)[][]int{ matrix :...
vector<int> spiralOrder(vector<vector<int>>& matrix) { vector<int> ans; if (matrix.empty()) return ans; int left = -1, top = -1, right = matrix[0].size(), bottom = matrix.size(); int x = 0, y = -1, dx = 0, dy = 1, cnt = right * bottom; while(cnt--){ x +=...
Java 版本代码如下: publicint[][] generateMatrix(intn) {int[][] res =newint[n][n];intvalue = 1;intleft = 0, right = n-1, top = 0, bottom = n-1;while(top < bottom && left <right) {//corresponding to the red partfor(intj = left; j < right; j++) { res[top][j]= ...
Can you solve this real interview question? Spiral Matrix - Given an m x n matrix, return all elements of the matrix in spiral order. Example 1: [https://assets.leetcode.com/uploads/2020/11/13/spiral1.jpg] Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
(matrix[rowtop][i]) # 取最后一列 for i in range(rowtop, rowbot): res.append(matrix[i][colright]) # 取最后一行 for i in range(colright, coleft, -1): res.append(matrix[rowbot][i]) # 取第一列 for i in range(rowbot, rowtop, -1): res.append(matrix[i][coleft]) # 第...
0054-leetcode算法实现之螺旋矩阵-spiralMatrix-python&golang实现,给你一个m行n列的矩阵 matrix,请按照顺时针螺旋顺序,返回矩阵中的所有元素。示例1:输入:matrix=[[1,2,3],[4,5,6],[7,8,9]]输出:[1,2,3,6,9,8,7,4,5]示例2:输入:matrix=[[1,2,3,4],[5,6,...
int m = matrix.length, n = matrix[0].length; // 计算圈数 int lvl = (Math.min(m, n) + 1) / 2; for(int i = 0; i < lvl; i++){ // 计算相对应的该圈最后一行 int lastRow = m - i - 1; // 计算相对应的该圈最后一列 ...
LeetCode-Spiral Matrix Description: Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. Example 1: AI检测代码解析 Input: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ]...
【CSON】LeetCode:885. Spiral Matrix III 0 0 2022-03-10 19:12:38未经作者授权,禁止转载点赞投币收藏分享官方网站:www.cspiration.com 微信号:cspiration01 微信公众号:北美CS求职 知识 职业职场 算法 留学生 程序员面试 北美留学 数据结构 leetcode 北美求职 算法题 程序员求职 北美...
classSolution{public:vector<int>spiralOrder(vector<vector<int>>&matrix){if(matrix.empty())returnvector<int>();intn=matrix.size(),m=matrix[0].size();vector<vector<bool>>f(n,vector<bool>(m,false));intdx[4]={0,1,0,-1},dy[4]={1,0,-1,0};//向右y + 1,向下x + 1, 向左y...