matrix[down][i]=count count+= 1down-= 1ifdirect == 3:foriinrange(down, up -1, -1): matrix[i][left]=count count+= 1left+= 1ifup > downorleft >right:returnmatrix direct= (direct + 1) % 4print(Solution().generateMatrix(3))...
https://leetcode.com/problems/spiral-matrix/ 题意分析: 输入一个m×n的数字矩阵。将这个矩阵按照螺旋方向输成一列。比如: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ] 输出[1,2,3,6,9,8,7,4,5] 题目思路: 这道题目只需要模拟这个过程。分四步,第一步行左到右,第二步从上到下...
down-=1ifdirect==3:foriinrange(down,up-1,-1):count+=1;matrix[i][left]=count left+=1ifcount==n*n:returnmatrix direct=(direct+1)%4
题目地址:https://leetcode.com/problems/spiral-matrix-ii/description/ 题目描述 Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example, Given n = 3, You should return the following matrix: [ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7,...
链接: https://leetcode-cn.com/problems/spiral-matrix/ 题目: 给定一个包含 m x n 个元素的矩阵(m 行, n 列),请按照顺时针螺旋顺序,返回矩阵中的所有元素。 示例 1: 输入: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ] 输出: [1,2,3,6,9,8,7,4,5] 示例 2: 输入: [ ...
[Leetcode][python]Spiral Matrix/Spiral Matrix II/螺旋矩阵/螺旋矩阵 II,SpiralMatrix题目大意将一个矩阵中的内容螺旋输出。注意点:矩阵不一定是正方形例子:输入:matrix=[[1,2,3],[4,5,6],[7,8,9]]输出:[1,2,3,6,9,8,7,4,5]解题思路看代码就可以理解代码classSolution(
Leetcode 题目解析之 Spiral Matrix II Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example, Given n = 3, You should return the following matrix: [ 1, 2, 3 , 8, 9, 4 ,
Can you solve this real interview question? Spiral Matrix - Given an m x n matrix, return all elements of the matrix in spiral order. Example 1: [https://assets.leetcode.com/uploads/2020/11/13/spiral1.jpg] Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Leetcode之 Spiral Matrix 问题 问题描述: Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. 示例: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ] You should return [1,2,3,6,9,8,7,4,5]. 问题来源... ...
题目:59. Spiral Matrix II题目链接:https://leetcode.com/problems/spiral-matrix-ii/description/这个题目的意思呢,是给定一个整数n,要求把数字1~n^2按照顺时针螺旋顺序填充到一个n维方阵里面。跟之前的螺旋方向遍历差不多吧,也是直接改的前一题的代码。Python:...