}intn = matrix[0].length;//columns//total rounds can be calculatd by using thisintrounds = (Math.min(m,n)+1)/2;for(inti=0; i<rounds; i++){//corresponding rowintcRow = m-i-1;//corresponding columnintcColumn = n-i-1;//corresponding row equals current rowif(i ==cRow){for(i...
classSolution{public:vector<int>spiralOrder(vector<vector<int>>& matrix){//0.函数入口判断vector<int> temp;if(!matrix.size())returntemp;//1.计算行列数intstart=0;introws=matrix.size();intcols=matrix[0].size();vector<int>ret(rows*cols); ret.clear();//2.打印循环while(start<<1<rows&&...
LeetCode 54. Spiral Matrix 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode Description Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. Example 1: Input:[[ 1, 2, 3 ],[ 4, 5, 6 ],[ 7, ...
https://leetcode.com/problems/spiral-matrix-ii/ 对于Spiral Matrix II, 这里我们只需要首先建立一个n*n的matrix,然后像I一样遍历即可。 上code class Solution(object): def generateMatrix(self, n): """ :type n: int :rtype: List[List[int]] """ if n == 0: return [] m, n = n, n ...
[leetcode] 54. Spiral Matrix Description Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order. Example 1: Input: [ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ] 1....
Can you solve this real interview question? Spiral Matrix - Given an m x n matrix, return all elements of the matrix in spiral order. Example 1: [https://assets.leetcode.com/uploads/2020/11/13/spiral1.jpg] Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Spiral Matrix III 0 0 2022-03-10 19:12:38未经作者授权,禁止转载点赞投币收藏分享官方网站:www.cspiration.com 微信号:cspiration01 微信公众号:北美CS求职 知识 职业职场 算法 留学生 程序员面试 北美留学 数据结构 leetcode 北美求职 算法题 程序员求职 ...
59. 螺旋矩阵 II - 给你一个正整数 n ,生成一个包含 1 到 n2 所有元素,且元素按顺时针顺序螺旋排列的 n x n 正方形矩阵 matrix 。 示例 1: [https://assets.leetcode.com/uploads/2020/11/13/spiraln.jpg] 输入:n = 3 输出:[[1,2,3],[8,9,4],[7,6,5]] 示例 2
classSolution{public:vector<int>spiralOrder(vector<vector<int>>&matrix){if(matrix.empty())returnvector<int>();intn=matrix.size(),m=matrix[0].size();vector<vector<bool>>f(n,vector<bool>(m,false));intdx[4]={0,1,0,-1},dy[4]={1,0,-1,0};//向右y + 1,向下x + 1, 向左y...
螺旋填充一个矩阵。 3、问题关键: 螺旋矩阵1 方向,坐标更新,边界条件。 4、C++代码: classSolution{public:vector<vector<int>>generateMatrix(intn){vector<vector<int>>res(n,vector<int>(n,0));intdx[4]={0,1,0,-1},dy[4]={1,0,-1,0};if(!n)returnres;intx=0,y=0,d=0;for(inti=0;...