Volume = 4/3 × 3.14 × 8Volume = 4/3 × 25.12Volume = 4/3 × 25.12 / 1 Volume = (4 × 25.12)/(3 × 1) Volume = (100.48) / 3 Volume = 33.49 cubic inch = 33.49 in.3Example #2 Find the volume of a sphere with a radius of 3 feet ...
× surface area of sphere + area of base = × 4π r2+ π r2 = 3π r2 = 3π (4)2 = 150.86 cm2 Problems about surface area of spheres Problem: What is the radius of the sphere given the surface area? Example: What is the radius of a sphere with a surface area of 900π?
20* Assume that the Earth is a sphere with radius 6371 km.The land are a on the surface of the Earth is 148 940000$$ k m ^ { 2 } $$.Use this information to show that the ratio of land are a to water are a is approximately 3:7. ...
radiusnumberGet or set the radius of the sphere. sphereShapeISphereShape sharedMaterialPhysicsMaterial isTriggerBooleanget or set the collider is trigger, this will be always trigger if using builtin. centerVec3get or set the center of the collider, in local space. ...
A 1.9 kg sphere with a radius of 0.08 m, is released at the top of a hill as shown.The sphere rolls without slipping, (therefore loss can be neglected) and reaches the bottom of the hill with a speed of 1.6 m/s. The moment of inertia of any sphere is s\ =2(_3mr^2) .What...
[X,Y,Z] = sphere(n) returns the x-, y-, and z- coordinates of a sphere with a radius equal to 1 and n-by-n faces. The function returns the x-, y-, and z- coordinates as three (n+1)-by-(n+1) matrices. example Plot Spheres sphere(___) plots the sphere without returning...
Read this how-to lesson to learn what steps you need to take to find the volume for a sphere with a radius of 4. Learn what the formula is and how...
-cid、 --clientid <user@domain> 字符串 [EAP-TLS]指定网络 RADIUS 服务器识别的身份验证 ID。 对于某些 EAP-TLS 网络是必需的。 -cn、 --configname 字符串 指定(最多 16 个字符的字符串,) 指定网络配置的名称。 -ip、--deviceip 字符串 (多设备,Windows 仅) 指定要用于此操作的设备 IP 地址。 仅...
is to approximate a sphere with radius $r$ by $n$ pyramids, each with a base area of $B$ and a height of $r$ (see picture below). Since the sum of the base areas is $n\times B$, the surface area of the sphere is approximately equal to $n\times B$, or $4r^2\times \pi...
whereris the radius in km. A similar fit toρ(r) to derive the pressure leads to a polynomial expression for pressure (in GPa) of P(r)=3.853676×102−3.083633×10−2r−1.184717×10−5r2, ((2)) again with radiusrin km. ...