在Scala中,可以使用Sorting.quickSort方法对数组进行排序。如果要对数组进行逆序排序,可以使用reverse方法将数组反转,然后再使用quickSort方法进行排序。 以下是一个示例代码: 代码语言:txt 复制 import scala.util.Sorting val arr = Array(5, 3, 8, 2, 1) val reversedArr = arr.reverse Sorting.quickSort(reve...
Quicksort is similar to MergeSort in that the sort is accomplished by dividing the array into two partitions and then sorting each partition recursively. In Quicksort, the array is partitioned by placing all items smaller than some pivot item before that item and all items larger than the piv...
function quickSortHelper(arrayInput, left, right) { let i = left; let j = right; let pivotPoint = arrayInput[Math.round((left + right) * .5)]; // Loop while (i <= j) { while (arrayInput[i] < pivotPoint) { i++; } while (arrayInput[j] > pivotPoint) { j--; } if (...
A rather straight forward solution is a two-pass algorithm using counting sort. First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. Could you come up with an one-pass algorithm using only co...
subSort(array,0, array.length - 1); System.out.print("排序后:\t");for(intnum : array) System.out.print(num+ " "); System.out.println(); } (2)结果: 排序前: 83 7 11 47 66 26 85 79 44 14 排序后: 7 11 14 26 44 47 66 79 83 85 ...
do_quick_sort(void* src, int src_sz, int n, cmp_func cmp, exc_func exchange, dbg_func dbg) { const int M = 0; int i,j,k; int l,r; char *kv, *ki, *kj; static int h = 0; F_S(); if (src == NULL || cmp == NULL || exchange == NULL) return 0; ...
After that, the two partitions are treated as independent input arrays and fed themselves to the Quicksort algorithm. Let’s seeLomuto’s Quicksortin action: 2.2. Performance with Repeated Elements Let’s say we have an array A = [4, 4, 4, 4, 4, 4, 4] that has all equal elements...
That’s because primitive types in Java are likeelementary particles in quantum mechanics. You can’t tell the difference between one 7 and another 7. Their value is all that defines them. Sort the array such [7, 6, 6, 7, 6, 5, 4, 6, 0] into [0, 4, 5, 6, 6, 6, 6, ...
); subSort(source, sign2 + 1, end); } } public static void main(String[] args) { int[] array = { 83, 7, 11, 47, 66, 26, 85, 79, 44, 14}; System.out.print("排序前: "); for (int num : array) System.out.print(num ...
In this chapter we present an important sorting algorithm of moderate complexity called "QUICKSORT". Once again, your main goal should be to gain additional problem solving experience by converting the conceptual description of this algorithm into a functioning computer program.Springer Berlin Heidelberg...